3 years ago

PLEASE HELP ME!!!! DUE TOMORROW

Mathematics

1 answer:

Aleks [24]3 years ago

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Find the third degree function that has zeros 7 and −11i, and a value of 663 when x=10.

slega [8]

Answer:

$y = x^3 - 7x^2 + 121x + 847$

Step-by-step explanation:

If -11i is a zero, its conjugate also is a zero, so the zeros are:

7, 11i and -11i.

So we can write the third degree function as:

$y = a(x-7)(x-11i)(x+11i)$

$y = a(x-7)(x^2+121)$

If the function has a value of 663 when x = 10, we have:

$663 = a(10-7)(10^2+121)$

$663 = a(3)(221)$

$a = 663/663 = 1$

So the function is:

$y = (x-7)(x^2+121)$

$y = x^3 - 7x^2 + 121x - 847$

6 0

4 years ago

Can someone please help me with this one

kakasveta [241]

Answer:

mhm

Step-by-step explanation:

4 0

3 years ago

9) 8.68354<br> the 5 is underlined and i need to know the decimal place

kozerog [31]

Answer:

ten-thousandths place

Step-by-step explanation:

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3 years ago

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3 divided by 1/4. How many groups of 1/4 are in 3

Lunna [17]

Answer:

there are 12 groups of 1/4 in 3

Step-by-step explanation:

multiply the reciprocal of 1/4 to 3 (division)

3×4(reciprocal of 1/4)= 12

that is the answer

6 0

3 years ago

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11. MP Persevere with Problems The Diaz family spent $38.25 on 3 large

fenix001 [56]

$12.75 per large pizza

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3 years ago

PLEASE HELP ME!!!! DUE TOMORROW ​

PLEASE HELP ME!!!! DUE TOMORROW