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Strike441 [17]
3 years ago
7

PLEASE HELP ME!!!! DUE TOMORROW ​

Mathematics
1 answer:
Aleks [24]3 years ago
4 0
What do you need help with?
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Which of the following are valid names for the given triangle? Check all that apply V ALOM BNLMZ C.PAMLZ DXZML WENZMO 72 FRAZMD​
crimeas [40]
The answer is C.pamlz dxzml
8 0
3 years ago
200 points if you answer my question i posted or maybe 100 i really dont know plz help me
KonstantinChe [14]

Answer:

I'll see if I could help.

Step-by-step explanation:

<em><u>< Sarah ></u></em>

8 0
2 years ago
Graph<br> plz step by step
Mazyrski [523]

Answer:

Step-by-step explanation:

The equation shown in the question can be seen graphed in the image attached below. As you can see with the graphed equation the variable x can be any real number except for -1. This is because a -1 would cause the denominator of the fraction to be equal to 0, and a fraction with a denominator as 0 is a null value and does not exist.

5 0
3 years ago
Adult men have heights that a normally distributed with a mean of 69.5 inches and a standard deviation of 2.4 inches. Adult wome
Aliun [14]

Answer:

Step-by-step explanation:

From the information given:

For Adult Men

Mean \mu = 69.5

Standard deviation \sigma = 2.4

observed value X = 74

For Adult Women

Mean \mu = 63.8

Standard deviation \sigma = 2.6

observed value X = 70

Therefore ; the values for their z  scores can be obtained in order to determine who is more unusually tall within his or her respective sex

For Adult Men :

z = \dfrac{X- \mu}{\sigma}

z = \dfrac{74- 69.5}{2.4}

z = \dfrac{4.5}{2.4}

z = 1.875

For Adult Women :

z = \dfrac{X- \mu}{\sigma}

z = \dfrac{70- 63.8}{2.6}

z = \dfrac{6.2}{2.6}

z = 2.3846

Thus; we can conclude that , the women is more unusually tall within his or her respective sex

5 0
3 years ago
Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.
tiny-mole [99]

let me edit your question as:

Which two equations are true?

<u>Eq1:</u>

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

<u>Eq2:</u>

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

<u>Eq3:</u>

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

<u>Eq1:</u>

(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\

<u>Eq2:</u>

<u></u>6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1<u></u>

<u>Eq3:</u>

2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>

<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>

8 0
3 years ago
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