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2 years ago

Mike found 74 seashells on the beach, he gave Mary some of his

Mathematics

2 answers:

Fed [463]2 years ago

7 0

Answer:

48 seashells

Step-by-step explanation:

you subtract 74-26 to get 48. to check your answer you do 74-48 to get 26.

mixas84 [53]2 years ago

6 0

Answer:

48 seashells were given to mary

Step-by-step explanation:

Mike has 74 seashells, and he gave some to mary.

__ + 26 = 74

The amount of seashells given to mary is that empty spot

So, let's subtract 74 by 26 and get 48 seashells given to mary

We can double check this answer by adding 48 and 26 to get 74, the original amount of seashells that mike had.

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The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

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3 years ago

Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

vivado [14]

Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.

The estimate and the sample size are given by:

$\pi = 0.36, n = 100$ .

Then the bounds of the interval are:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836$

The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago