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GrogVix [38]
3 years ago
9

How does an increase in concentration affect the rate of a reaction?

Chemistry
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

Option (a) it speeds the reaction up

Explanation:

Increasing the concentration of a reactants speed up the reaction because it leads to effective collisions which in turn speeds up the reaction

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HELP!!!!!!!!!!!! ASAP!!!!!!!!!!!!!!!!!!! CHEMISTRY TEST!!!!!!!!!!!!!! 53 POINTS
lbvjy [14]

Answer:

9.1 KJ

Explanation:

First we must find the number of moles of HBr involved;

number of moles of HBr= mass of HBr/ molar mass of HBr

But molar mass of HBr= 80.91 g/mol

Given mass of HBr from the question= 20.1g

Hence;

Number of moles of HBr= 20.1 g/80.91g

Number of moles of HBr= 0.25 moles of HBr

If 2 moles of HBr has a heat of formation of 72.80KJ

Then 0.25 moles of HBr will have a heat of formation of 0.25× 72.80/2= 9.1 KJ

Therefore; 20.1 g of HBr will have a heat of formation of 9.1 KJ

3 0
3 years ago
A car moved 20km East and 70km West. What is the distance?
Nutka1998 [239]

Answer:

50km

Explanation:

70km - 20km = 50 kilometers

6 0
3 years ago
2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh
Rufina [12.5K]
The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.
8 0
3 years ago
Read 2 more answers
Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .
Nimfa-mama [501]

Answer:

\Delta H=-28.08 \frac{kJ}{mol}

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}

Which accounts for an exothermic chemical reaction.

Regards.

7 0
4 years ago
If 3.85 mL of 10.0 M NaOH is used for a reaction, calculate the number of moles of NaOH that were used.
Lena [83]

The number of mole of NaOH that was used, given that 3.85 mL of 10.0 M NaOH is used in the reaction is 0.0385 mole

<h3>How do I determine the number of mole of NaOH?</h3>

We know that molarity is related to number of mole and volume according to the following formula:

Molarity = number of mole / Volume

With the above formula, we can determine the number of mole of NaOH. Details below

The following data were obtained from the question:

  • Volume = 3.85 mL = 3.85 / 1000 = 0.00385 L
  • Molarity = 10.0 M
  • Number of mole of NaOH =?

Molarity = number of mole / Volume

Cross multiply

Number of mole = molarity × volume

Number of mole of NaOH = 10 × 0.00385

Number of mole of NaOH = 0.0385 mole

Thus, the number of mole of NaOH is 0.0385 mole

Learn more about number of mole:

brainly.com/question/20522500

#SPJ1

4 0
2 years ago
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