Answer:
fundamental frequency in helium = 729.8 Hz
Explanation:
Fundamental frequency of an ope tube/pipe = v/2L
where v is velocity of sound in air = 340 m/s; λ is wave length of wave = 2L ; L is length of the pipe
To find the length of the pipe,
frequency = velocity of sound / 2L
272 = 340 / 2 L
L = 0.625 m
If the pipe is filled with helium at the same temperature, the velocity of sound will change as well as the frequency of note produced since velocity is directly proportional to frequency of sound.
Also, the velocity of sound is inversely proportional to square root of molar mass of gas; v ∝ 1/√m
v₁/v₂ = √m₂/m₁
v₁ = velocity of sound in air, v₂ = velocity of sound in helium, m₁ = molar mass of air, m₂ = molar mass of helium
340 / v = √4 / 28.8
v₂ = 340 / 0. 3727
v₂ = 912.26 m /s
fundamental frequency in helium = v₂ / 2L
fundamental frequency in helium = 912.26 / (2 x 0.625)
fundamental frequency in helium = 729.8 Hz
Answer:
Explanation:
The law of multiple proportions states that if two elements X and Y combine together to form more than one compound, then the several masses of X which chemically combine with a fixed mass of Y is in simple ratio.T
FIRST CASE ;
- Molar mass of Nitrogen gas = 28 g/mol
- Number of moles of Nitrogen gas = Mass/molar mass = 3.50/28 = 0.125 moles
- Number of moles of Oxygen gas = Mass/molar mass = 2.00/32 = 0.0625 moles
- Hence the ratio of number of moles of N2 to O2 will be 0.1295 : 0.0625 or 2:1
- Similarly for the SECOND CASE ;
- Molar mass of Nitrogen gas = 28 g/mol
- Number of moles of Nitrogen gas = Mass/molar mass = 0.875/28 = 0.03125 moles
- Number of moles of Oxygen gas = Mass/molar mass = 1/32 = 0.03125 moles
- Hence the ratio of number of moles of N2 to O2 will be 0.03125 : 0.03125 or 1:1
They will melt at the same rate because they contain the same matter
hope this helps and good luck on your project!!!!