<h3>
Answer:</h3>
7.4797 g AlF₃
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN] 2AlF₃ + 3K₂O → 6KF + Al₂O₃
[Given] 15.524 g KF
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol AlF₃ = 6 mol KF
Molar Mass of Al - 26.98 g/mol
Molar Mass of F - 19.00 g/mol
Molar Mass of K - 39.10 g/mol
Molar Mass of AlF₃ - 26.98 + 3(19.00) = 83.98 g/mol
Molar Mass of KF - 39.10 + 19.00 = 58.10 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 5 sig figs.</em>
7.47966 g AlF₃ ≈ 7.4797 g AlF₃
Answer:
a.Fold × unfold
b. noisy × peaceful
c. uncertainly × certainly
4x − 8x= −3
Step 1: Simplify both sides of the equation.
4x−8x = −3
4x + −8x= −3
(4x + −8x) = −3 (Combine Like Terms)
−4x = −3
Step 2: Divide both sides by -4.
−4x / −4
−3
- / −4
so your answer will be x= 3/4
.
Answer:
The period number tells which is the highest energy level occupied by the electrons.
Explanation:
- The period number (denoted by n) is the outer energy level that is occupied by electrons in an atom.
- The period number that an element is in, is the number of energy levels that the element has.
- When we move across a period from left to right in a periodic table the number of electrons in atoms increases within the same orbit.