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sertanlavr [38]
3 years ago
5

2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh

at class of compound is it, and what feature distinguishes it as that class?
Chemistry
2 answers:
Rufina [12.5K]3 years ago
8 0
The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.
MAVERICK [17]3 years ago
8 0

Answer:

(C₆H₁₂) 3,4-hexene demonstrating the double bond between 3rd and 4th carbon is shown below:  

CH₃-CH₂-CH=CH-CH₂-CH₃

The suffix ene signifies that it comprises double bond in it between the atoms of carbon that comes under alkene. The Greek prefix hex means 6, and in hexene, it signifies that it comprises six carbon atoms in a molecule. The double bond in the compound is found in between 3 and 4 carbons.  

This can also demonstrate symmetry that comes under symmetrical alkene in such molecule the double bonded carbons exhibit same ligands or a similar number of carbons on both the sides.  

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The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?
tino4ka555 [31]
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
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x = 1.5x10^-3 M

The molar solubility would be </span>1.5x10^-3 M.
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Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh
Ann [662]

Answer:

See explanation and image attached

Explanation:

The  Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi.  R is an alkyl or aryl group.

They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.

In this particular instance, we intend to synthesize propylcyclohexane. The structure of the  lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.

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