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s2008m [1.1K]
3 years ago
5

P and Q each stand for whole numbers. P + Q = 1000 P is 150 greater than Q. Calculate the numbers P and Q ?

Mathematics
1 answer:
Artemon [7]3 years ago
8 0
P+Q=1000
Q+150=P
Plug (Q+150) for P.
(Q+150)+Q=1000
2Q=850
Divide both sides by 2.
Q=425
Now use 425 to find P.
425+P=1000
Subtract 425 from both sides.
P=575
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In a random sample of 800 seniors at Mill Creek High School, 100 students are asked if they prefer graduation at the High School
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Step-by-step explanation:

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3 years ago
The measures of complementary angles have a sum of 90 degrees.Angle A and angle B are complimentary, and their measures have a d
777dan777 [17]

Answer:

The measure of the angles are 55° and 35°

Step-by-step explanation:

Sum of two angles that are complement of each other are 90.

The angles are A and B, so we can write:

A + B = 90

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The difference is 20. Let A be the greater of them, so we can write equation 2 as:

A - B = 20

Now, we add up both equations, eliminate B and solve for A first:

A + B = 90

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And now the measure of B:

A + B = 90

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5 0
4 years ago
The NWBC found that 42.1% of women-owned businesses provided retirement plans contributions.
Natasha_Volkova [10]

Answer:

Sample size of 586 or higher.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What sample size could be 95% confident that the estimated (sample) proportion is within 4 percentage points of the true population proportion?

Sample size of at least n when M = 0.04

42.1% of women-owned businesses provided retirement plans contributions, which means that p = 0.421. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.421*0.579}{n}}

0.04\sqrt{n} = 0.9677

\sqrt{n} = \frac{0.9677}{0.04}

\sqrt{n} = 24.19

\sqrt{n}^{2} = (24.19)^(2)

n = 585.2

We need a sample size of 586 or higher.

3 0
3 years ago
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jekas [21]

Answer:

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hope it is ❤❤❤❤

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