Answer:
I'm really sorry I can't tell you the answer because you have to measure the angle by yourself using a protractor. But I gave you information about types of angles if you got the degree of angles ( e.g 90 degrees). Hope it helped.
Step-by-step explanation:
acute angle-an angle between 0 and 90 degrees
right angle-an 90 degree angle
obtuse angle-an angle between 90 and 180 degrees
straight angle-a 180 degree angle
In one day, there are 24 hours. In 1 hour, there are 3,600 seconds. So, that means that there are 86,400 seconds. Also, in 1 day, the short hand which denotes the number of hours, makes 2 revolutions around the clock. Its distance traveled would be twice the perimeter of the circle.
Distance traveled by hour hand = 2(2πr) = 4πr₁
In 60 s, the long hand, which denotes numbers of minutes, makes one revolution around the clock. Since there are 86,400 seconds in a day, that would be a total of 1,440 revolutions.
Distance traveled by minute hand = 1,440(2πr) = 2,880πr₂
Difference = 2880πr₂ - 4πr₁ = 4π(720r₂ - r₁), where r₁ is the length of hour hand and r₂ is the length of minute hand.
Answer: y = (x + 5)² + 8
<u>Step-by-step explanation:</u>
y = x²
left 5 units: y = (x + 5)²
up 8 units: y = (x + 5)² + 8
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
