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3 years ago

Can someone help me pls 25 points

Mathematics

2 answers:

Tamiku [17]3 years ago

7 0

Answer:

Step-by-step explanation:

(2x)³= 2x*2x*2x

(2x)³=8x³

Ivahew [28]3 years ago

3 0

Answer:

8x^{3}

Step-by-step explanation:

By the laws of exponents we have to multiply each term in the parenthesis by the exponent on the outside:

(2x)^{3} would be equal to = 8x^{3}

Another way we could write would be (2x)(2x)(2x) = 8x^{3}

The second one is the same, just fill in as 8 and 3

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1. Given the points A (2, 14) and B (17, -6).

Scrat [10]

Answer:

Step-by-step explanation:

5 0

2 years ago

For the function f(t)+Pe^rt, if P = 8 and r = 0.08, then what is the value of f(8) to the nearest tenth?

Bogdan [553]

F(t) = P.e^(r.t) [ and not as you wrote it f(t)+Pe^rt]
plug in:

f(t) = 8.e^(0.08t) (where e = 2.718 and t=8 given, f(8))
f(8) = 8.(2.718)^(0.08*8) = 21.74^(0.64)

f(8) = 7.17

4 0

3 years ago

Read 2 more answers

A study conducted at a certain college shows that 65% of the school's graduates find a job in their chosen field within a year

alexdok [17]

Answer: 0.009

Step-by-step explanation:

Formula we use here : Binomial distribution formula

Probability of getting success sin x trial = $P(X)=^nC_xp^x(1-p)^{n-x}$ , where n is the sample size and p is the probability of success in each trial .

Given : A study conducted at a certain college shows that 65% of the school's graduates find a job in their chosen field within a year after graduation.

i.e. p= 0.65

Sample size : n= 11

Now, the probability that 11 randomly selected graduates all find jobs in their chosen field within a year of graduating:-

$P(X)=^{11}C_{11}(0.65)^{11}(1-0.65)^{11-11}\\\\=(1)(0.65)^{11}(1)\\\\=0.00875078317401\approx0.009$

Hence, the probability that 11 randomly selected graduates all find jobs in their chosen field within a year of graduating = 0.009

8 0

3 years ago

For the given term, find the binomial raised to the power , whose expansion it came from: 10a ^ 3 * b ^ 2 .

9966 [12]

Answer:

i dont know sorry

Step-by-step explanation:

7 0

3 years ago

A simple random sample of 50 items from a population with 7 resulted in a sample mean of 35.

Vilka [71]

The 90% , 99% confidence interval for the population mean is 32.145 < $\rm \mu$ < 35.855 and 31.093 < $\rm \mu$ < 36.907

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

Total Population = 50

Mean = 35

The confidence interval is given by

$\rm CI = \mu + z \dfrac{s}{\sqrt n}$

$\rm \mu$ is the mean

z is the confidence level value

s is the standard deviation

n is the population width

(a) The 90% confidence interval for the population mean

90% $\rm \alpha / 2$ = 0.05

Z = 1.64

34 $\rm \pm$ 1.64 * 8 / √50

34 $\rm \pm$ 1.855

32.145 < $\rm \mu$ < 35.855

(b) The 99% confidence interval for the population mean

99% $\rm \alpha / 2$ = 0.005

Z=2.57

34 $\rm \pm$ 2.57 * 8 / √50

34 $\rm \pm$ 2.907

31.093 < $\rm \mu$ < 36.907

Therefore the confidence interval for population mean has been determined.

The complete question is

A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.

a. Provide a 90% confidence interval for the population mean

b. Provide a 99% confidence interval for the population mean

To know more about Probability

brainly.com/question/11234923

#SPJ1

8 0

2 years ago