Answer: C
Explanation: they will never touch
Answer:
so lets remember the formula for interest first.
#lightbulb
here it is A = P(1 + rt)
all we really have to do is plug in our rates, principles, and time into equation.
P = $800
t = 2 years
r = 6.5% or as a decimal 0.065
now lets look at our new equation that finally has numbers in it
A = 800[1 +(0.065)(2)] first lets take care of the 0.065 and 2 by multiplying them together. thus our new equation.
A = 800(1+ 0.13) then we add the 1 to the 0.13 and get 1.13
800(1.13) from here we just multiply and that equals 904
since we are looking for what is earned we take 904 and subtract 800 to get that answer. Here is the math.
904 - 800 = 104
he made 104 dollars in 2 years
hope this is right
Step-by-step explanation:
Answer:
This may not be entirely satisfied proof but you should get the idea.
Proof: Start with 1 = -1.
Then we know that if a= b then a + c = b + c and also a / c = b / c.
So we can add 1 to both sides.
We have 1 + 1 = -1 + 1 ⇒ 2 = 0.
Now divide both sides by 2 and we would have 1 = 0.
Now add both sides by 1. This yields 2 = 1.
Therefore if 1 = -1 then 2 = 1.
QED
Answer:
Step-by-step explanation:
7*4a=-14
7-7*4a=-14-7
4a=-21
a=-5.25
Answer:
A) THE MEAN DIFFERENCE = 22.2 - 20 = 2.2
B) HERE WE NEED TO CALCULATE THE MARGIN OF ERROR
AS GIVEN THE VARIANCE = 384
THEREFORE STANDARD DEVIATION = (384)^(1/2) = 19.59
THE MARGIN OF ERROR = STANDARD DEVIATION / SQRT(N) = 19.59/SQRT(25) = 19.59/5 = 3.91
C) AS THE SAMPLE SIZE IS LESS THEN 30 THEREFORE WE WILL DO IT BY THE T TEST
We need to test the null H0 : µ = 20 against the TWO-sided alternative H1 : µ\neq 20, at level α = 0.05. Since n is SMALL, we will do a SMALL-sample T-test. The rejection region is T >Tα = 1.96OR T<-Tα = -1.96, using the normal table.
T= (X − µ0) /(S/√ n) = (22.2 − 20)/( 19.59/ √ 25) = 0.56 Since T = 0.56 < 1.96, H0 is ACCEPTED. Thus, there is significant evidence at 5% signifi- cance level .
Step-by-step explanation:
