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3 years ago

Micro-Tech, Inc.'s stock closed at 7.375, up 0.125. Yesterday's closing price was

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

Answer is 7.25

Today's price was: 7.375

The question is saying that it went up .125 from yesterday's total, which means you have to take away .125 to get back to yesterday's total closing price

7.375 - .125 = 7.25

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Solutions to this quadratic<br> F(x) = x^2 + x - 2

dybincka [34]

Answer:

x = -2 & x = 1

Step-by-step explanation:

4 0

3 years ago

Marcy buys a box containing 5 pizzas at the supermarket. The box of pizzas costs $24.25 and Marcy is charged an additional $1.21

aev [14]

If my math is correct it isn't reasonable and my math tells me it was $4.99 per pizza

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4 years ago

Read 2 more answers

Write an equation for the nth term of<br> the arithmetic sequence: <br> 15,28,41 ....

11111nata11111 [884]

Answer:

The equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

Step-by-step explanation:

We need to write an equation for the nth term of the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: $a_n=a_1+(n-1)d$

Where $a_n$ is the nth term, $a_1$ is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

$a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13$

So, the common difference d is 13

Now, equation for nth term will be:

$a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2$

So, the equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

where n=1,2,3..

4 0

3 years ago

Which equation represents a slope of −4<br> and y-intercept of (0, 2) ?

aksik [14]

Answer:

y = - 4x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 4 and y- intercept = (0, 2) ⇒ c = 2

y = - 4x + 2 ← equation in slope- intercept form

5 0

4 years ago

The center of a hyperbola is (-5,8). The length of the conjugate axis is 6 units, and the length of the transverse axis is 14 un

serious [3.7K]

Answer:

$(\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

Step-by-step explanation:

IMPORTANT FORMULA: the standard equation of a hyperbola whose transverse axis is parallel to the y axis is:

$(\frac{x-h}{a}) ^{2}+ (\frac{y-k}{b} )^{2} =1$

where, (h,k) : center of the hyperbola

a : semi conjugate axis [ length of conjugate axis/2]

b: semi transverse axis [ length of transverse axis/2]

so, here a=3, b=7, [h,k]=[-5,8]

by substituting these values in the above given formula,

the equation of the hyperbola in standard form is :

$(\frac{x-(-5)}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

$(\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

8 0

4 years ago