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Artyom0805 [142]
3 years ago
8

Find the real zeros of the following function, and plot them on the graph. f(x)=(x^4-16)(x^2+3x-18)

Mathematics
2 answers:
adoni [48]3 years ago
5 0

Answer:

Given function,

f(x)=(x^4-16)(x^2+3x-18)

=((x^2)^2-(4)^2)(x^2+(6-3)x-18)

=(x^2-4)(x^2+4)(x^2+6x-3x-18)

=(x-2)(x+2)(x^2-(2i)^2)(x(x+6)-3(x+6))

=(x-2)(x+2)(x+2i)(x-2i)(x-3)(x+6)

For zeros of function f(x),

f(x) = 0

\implies (x-2)(x+2)(x+2i)(x-2i)(x-3)(x+6)=0

By zero product property,

We get,

x = 2, -2, -2i, 2i, 3, -6

Hence, the real roots of f(x) are 2, -2, 3, -6.

Also, the roots lie at the point where a function intersects the x-axis.

Hence, the positions of the roots of f(x) in the graph are ,

(2, 0), (-2, 0), (3, 0) and (-6, 0)

vivado [14]3 years ago
4 0

the 0 are 2, 3 and -6. ....

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C. 1050

Step-by-step explanation:

To find the area of a rectangle, it is length * width * height

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175 * 6 = 1050

2. Answer:

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Step-by-step explanation:

To find the missing dimension of a rectangle, you can easily just divide the total by each dimension

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72 divided by 9 = 8

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4 years ago
What is the answer to this problem
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A

Step-by-step explanation:

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kay:

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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Every parabola is <em>symmetric</em> about its axis, which means that if it were folded along its axis, the two parts would match.  The fold or line that divides the parabola into two matching halves is called the axis of symmetry. The highest or lowest point of a parabola is its vertex, which is on the axis of symmetry, <em>x = h</em>.

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