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3 years ago

Find geometric mean between 3 and 6

2 answers:

4 0

Call the geometric mean ' G '.

Then (3 / G) = (G / 6)

This is a proportion, and may be "cross-multiplied":

G² = 18

G = √18 = about 4.2426... (rounded)

zalisa [80]3 years ago

3 0

$geometric\ mean\ between \ a\ and\ b\ = \sqrt{a\cdot b} \\----------------------\\\\geometric\ mean= \sqrt{3\cdot6} = \sqrt{3\cdot3\cdot2} =3\cdot \sqrt{2}$

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900 + 50 + 4 + 0.7<br> Please help me

Ann [662]

Answer:

954.7

Step-by-step explanation:

Hope that this is helpful.

Have a nice day.

4 0

2 years ago

Pfvr algm me ajuda nessa

Sergio [31]

Answer:

Which is a risk factor for cardiovascular disease

Group of answer choices

stress

excess weight

Tobacco use

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Step-by-step explanation:

7 0

2 years ago

The table shows the average weight of animals. How many more tons does a blue whale weigh than an African elephant? Explain how

AVprozaik [17]

Answer:

The African elephant weighs <u>111.5 tons</u> less than a blue whale.

Step-by-step explanation:

Given:

Animal Weight(pounds)

African Elephant 15,000

Blue Whale 238,000

Now, to find the weight of how more tons does a blue whale weigh than an African elephant.

As given, 1 ton = 2,000 pounds.

So, to convert the weight from pound to tons by dividing:

African elephant $=15000\div 2000=7.5\ tons.$

Blue whale $=238000\div 2000=119\ tons.$

Now, to get the weight of how more tons is blue whale weigh than an African elephant we subtract:

$Blue\ whale - African\ elephant$

$=119 tons-7.5tons$

$=111.5\ tons$

Therefore, the African elephant weighs 111.5 tons less than a blue whale.

8 0

2 years ago

Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial

Diano4ka-milaya [45]

Answer:

not a factor

Step-by-step explanation:

If (x - 3) is a factor then f(3) = 0

f(x) = 2x² - 4x + 30

f(3) = 2(3)² - 4(3) + 30 = 18 - 12 + 30 = 36 ≠ 0

Since f(3) ≠ 0 then (x - 3) is not a factor of f(x)

3 0

3 years ago

If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me

VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]

8 0

3 years ago