So,
"The sum of five times a number and -6"
5n + -6 or 5n - 6
"is -2"
= -2
5n - 6 = -2
Add 6 to both sides.
5n = 4
Divide both sides by 5.
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer:
Move it to 2 place to the right
Step-by-step explanation:
4.003×100
=400.3
It can be observed that the dot in front of 4 has been shifted in two times to the front giving us 400.3
But in the case of division,it will be two places to the left...
I hope you understand
log x ( 5 × 12 ) = 7
x^7 = 60
..................................