Number of electron pairs = \frac{1}{2}[V+N-C+A]
2
1
[V+N−C+A]
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
SbCl_5SbCl
5
:
In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.
The number of electron pairs are 5 that means the hybridization will be sp^3dsp
3
B and geometry of the molecule will be trigonal bipyramidal.
If one or more nucleotide pairs are deleted from a DNA strand, this is known as a frameshift mutation
<h3>
Define Frameshift Mutation</h3>
Insertions or deletions in the genome that are not multiples of three nucleotides are referred to as frameshift mutations. They are a particular class of insertion-deletion (indel) alterations that are present in polypeptides' coding sequences. Here, there are no multiples of three in the number of nucleotides that are added to or subtracted from the coding sequence. They may result from really basic alterations like the insertion or deletion of a single nucleotide.
<h3>
Frameshift mutations' effects</h3>
One of the most harmful modifications to a protein's coding sequence is a frameshift mutation. They are quite prone to produce non-functional proteins that frequently interfere with a cell's metabolic processes and result in significant alterations to polypeptide length and chemical makeup. Frameshift mutations can cause the mRNA to stop translating too soon and create an extended polypeptide.
Learn more about Frameshift mutations here:-
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0.1 km
2cm/year * 5000 yrs = 10000 cm
1cm= .01 m
1km = 1000 m
so the answer is 0.1 km
<h2>Step 1 : Identify the given </h2>
Volume = 250mL
Density = 1.19 g/ML
<h2>Step 2 . Calculate the mass of HCL </h2>
Density = mass/volume
∴Mass = Density * Volume
= 1.19g/mL* 250mL
= 297,5g
<h2>Step 3 : Calculate the total mass of the solution, given that concentration HCL is 38% </h2>
Mass of the total solution can be calculated by the following :
38% = Mc /297.5 * 100
Mc = 38/100 *297.5
= 113.05grams
• Finally, this means that mass of the total solution of 0.125M HCL i,s 113grams, ,you would use this mass to prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0%