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Alex Ar [27]
3 years ago
7

Anyone know what the answer is?

Chemistry
2 answers:
musickatia [10]3 years ago
8 0
I say the second one
erastova [34]3 years ago
3 0
The answer is b im pretty sure
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In a neutral solution the concentration of _____. a. hydrogen ions is less than the concentration of hydroxide ions b. water mol
Georgia [21]

Answer:

In a neutral solution the concentration of hydrogen ions is equal to the concentration of hydroxide ions

Explanation:

When:

[H⁺] > [OH⁻]  the pH is acid, so the solution is practically acid.

When

[H⁺] < [OH⁻], the pH is basic, so the solution is practically basic

In neutral solutions:

[H⁺] = [OH⁻], so the pH is neutral (7)

pH > 7 → BASIC SOLUTIONS

pH < 7 → ACID SOLUTION

5 0
3 years ago
Which of the following is a physical property of matter
Black_prince [1.1K]

Answer: Physical properties of matter include color, hardness, malleability, solubility, electrical conductivity, density, melting point, and boiling point. For the elements, color does not vary much from one element to the next

3 0
3 years ago
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The stops in a chemical reaction means ______ A. Yields or makes B. Difference C. Sum D. Together
Sergeu [11.5K]
The answer will be A.
3 0
3 years ago
Which of the following characteristics do Element I and Element I have in common?
Nesterboy [21]

Answer:

Option C. The same number of energy levels.

Explanation:

From the diagram given above, element (i) belong to group 2 while element (ii) belong to group 6.

Also, both element i and ii belong to the same period (i.e period 4). This simply means that both element i and ii have the same number of energy levels.

NOTE: Elements in the same period have the same number of shells of electrons which simply means they have the same energy levels.

5 0
3 years ago
The enthalpy of combustion of n-octane, C8H18, is –4.79 × 107 J/kg. What is the enthalpy of combustion expressed in kJ/g?
SIZIF [17.4K]

Answer:

47,9 kJ/g

Explanation:

The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:

-4,79x10^7J/kg \frac{1kJ}{1000J} \frac{1kg}{1000g} = <em>47,9kJ/g</em>

<em></em>

I hope it helps!

6 0
4 years ago
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