10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
Explanation:
Step 1: To make Si equal on both sides. put 10 in front of HSiCl3
10 HSiCl3+ H2O →H10Si10O15+ HCl
Step 2: By putting 30 in front of HCl, Cl can be balanced
10 HSiCl3+ H2O →H10Si10O15+ 30 HCl
Step 3: Now, balance O by putting 15 in front of H2O
10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
Hence the balanced equation is:
10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
This type of energy would be called reaction energy.
Answer:
If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.
Explanation:
Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure
V ∝ 1/P or V₁·P₁ = V₂·P₂
Where:
V₁ = Initial volume
V₂ = Final volume = V₁/2
P₁ = Initial pressure = 832 torr
P₂ = Final pressure = Required
From V₁·P₁ = V₂·P₂ we have,
P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)
P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr
