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lakkis [162]
3 years ago
6

What element has two electrons in the outer most shell

Chemistry
1 answer:
RUDIKE [14]3 years ago
4 0

Answer:

Helium

Explanation:

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answer now please Which device can be used to separate nails from sawdust most efficiently? A. strainer B. magnet C. colander D.
e-lub [12.9K]
A magnet because it will remove only metal and not the saw dust

Hope this helps
6 0
3 years ago
Read 2 more answers
What would be the major product obtained from hydroboration–oxidation of the following alkenes?
zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>

In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
Name an object that the magnet would repel
Nataly_w [17]
The negative side of another magnet
3 0
3 years ago
@ What is the wavelength of a radio wave having a frequency of 3.75 X 107 Hz?
aniked [119]

Answer:

8 m

Explanation:

3.0 x 10*8 divided by 3.75 x 10*7 = 8 m

6 0
2 years ago
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
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