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Elanso [62]
3 years ago
13

Percy solved the equation x2 + 7x + 12 = 12. His work is shown below. Is Percy correct? Explain. 1. (x + 3)(x + 4) = 12 2. x + 3

= 12 or x + 4 = 12 3. x = 9 or x = 8
Mathematics
2 answers:
nevsk [136]3 years ago
8 0

Sample Response: Percy is not correct because he applied the zero product property to a factored expression that was not equal to 0. He should have subtracted 12 from both sides to get x2 + 7x = 0 before factoring. The correct solutions are 0 and -7.


RoseWind [281]3 years ago
4 0
Percy is not correct because he applied the zero product property to a factored expression that was not equal to 0. He should have subtracted 12 from both sides to get x2 + 7x<span> = 0 before factoring. The correct solutions are 0 and -7.</span>
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Solve the problem, calculate the line integral of f along h
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The curve \mathcal H is parameterized by

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\displaystyle\int_{\mathcal H}f(x,y,z)\,\mathrm ds=\int_{t=0}^{t=2\pi}f(X(t),Y(t),Z(t))\sqrt{\left(\frac{\mathrm dX}{\mathrm dt}\right)^2+\left(\frac{\mathrm dY}{\mathrm dt}\right)^2+\left(\frac{\mathrm dZ}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}Y(t)^2\sqrt{(-R\sin t)^2+(R\cos t)^2+P^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}R^2\sin^2t\sqrt{R^2+P^2}\,\mathrm dt
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You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function f:\mathbb R^n\to\mathbb R, we have gradient \nabla f:\mathbb R^n\to\mathbb R^n. The theorem itself then says that the line integral of \nabla f(x,y,z)=\mathbf f(x,y,z) along a curve C parameterized by \mathbf r(t), where a\le t\le b, is given by

\displaystyle\int_C\mathbf f(x,y,z)\,\mathrm d\mathbf r=f(\mathbf r(b))-f(\mathbf r(a))

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3 years ago
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Korolek [52]
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7 0
3 years ago
Can someone help with my homework?
Len [333]

Answer:

1a) -\frac{15}{4}

1b) \frac{95}{33}

2a) -84

2b) 1

3a) \frac{171}{550}

3b) 4\frac{2}{7}

Step-by-step explanation:

For the first equation, let's use \frac{-a}{b} =\frac{a}{-b} =-\frac{a}{b} to right a new fraction.

Step 1- Reduce the fraction with 4.

-\frac{\frac{12/4}{4/4} }{\frac{4}{5} } =  -\frac{3}{\frac{4}{5} }

Step 2- Simplify the complex fraction(LCD or Least Common Denominator).

-\frac{3}{\frac{4}{5} } = -\frac{15}{4}

An alternative form for this fraction is -3\frac{3}{4}  or -3.75.

For the second equation..

Step 1- Convert the mixed number to an improper fraction.

\frac{6\frac{3}{9} }{\frac{11}{5} } = \frac{\frac{57}{9} }{\frac{11}{5} }

Step 2- Simplify the complex fraction.

\frac{\frac{57}{9} }{\frac{11}{5} } = \frac{95}{33}

An alternative form for this fraction is 2\frac{29}{33}  or 2.87.

For the third equation use \frac{-a}{b} =\frac{a}{-b} =-\frac{a}{b}...

Step 1- Simplify the complex fraction(LCD).

-\frac{7}{\frac{1}{12} } = -84

For the fourth equation...

Write the fraction as a division.

\frac{12}{8}÷\frac{3}{2}

To divide a fraction, multiply by the reciprocal of that fraction.

\frac{12}{8} *\frac{2}{3} = \frac{12*2}{8*3}

Reduce the fraction with 3.

\frac{4*2}{8}= \frac{4}{4} = 1

For the fifth equation...

Convert the mixed number to an improper fraction.

\frac{-1\frac{8}{11} }{-5\frac{5}{9} } = \frac{-\frac{19}{11} }{-\frac{50}{9} }

Reduce the fraction with -1, this eliminates the negative sign.

Simplify the complex fraction.

\frac{\frac{19}{11} }{\frac{50}{9} } = \frac{171}{550}

An alternative form for this fraction is 0.3109.

For the sixth equation..

Write the fraction as a division.

\frac{3}{7}÷\frac{1}{10}

To divide by a fraction, multiply by the reciprocal of that fraction.

\frac{3}{7}×10= \frac{3*10}{7}

Multiply the numbers.

\frac{3*10}{7} = \frac{30}{7}

Alternative form of this fraction is 4\frac{2}{7} or 4.285714.

Hope this helps! :)

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