Question

Can someone help with my homework?

Answer 1

Answer:

1a) $-\frac{15}{4}$

1b) $\frac{95}{33}$

2a) $-84$

2b) 1

3a) $\frac{171}{550}$

3b) $4\frac{2}{7}$

Step-by-step explanation:

For the first equation, let's use $\frac{-a}{b} =\frac{a}{-b} =-\frac{a}{b}$ to right a new fraction.

Step 1- Reduce the fraction with 4.

$-\frac{\frac{12/4}{4/4} }{\frac{4}{5} } = -\frac{3}{\frac{4}{5} }$

Step 2- Simplify the complex fraction(LCD or Least Common Denominator).

$-\frac{3}{\frac{4}{5} } = -\frac{15}{4}$

An alternative form for this fraction is $-3\frac{3}{4} or -3.75$.

For the second equation..

Step 1- Convert the mixed number to an improper fraction.

$\frac{6\frac{3}{9} }{\frac{11}{5} } = \frac{\frac{57}{9} }{\frac{11}{5} }$

Step 2- Simplify the complex fraction.

$\frac{\frac{57}{9} }{\frac{11}{5} } = \frac{95}{33}$

An alternative form for this fraction is $2\frac{29}{33} or 2.87$.

For the third equation use $\frac{-a}{b} =\frac{a}{-b} =-\frac{a}{b}$...

Step 1- Simplify the complex fraction(LCD).

$-\frac{7}{\frac{1}{12} } = -84$

For the fourth equation...

Write the fraction as a division.

$\frac{12}{8}$÷$\frac{3}{2}$

To divide a fraction, multiply by the reciprocal of that fraction.

$\frac{12}{8} *\frac{2}{3} = \frac{12*2}{8*3}$

Reduce the fraction with 3.

$\frac{4*2}{8}= \frac{4}{4} = 1$

For the fifth equation...

Convert the mixed number to an improper fraction.

$\frac{-1\frac{8}{11} }{-5\frac{5}{9} } = \frac{-\frac{19}{11} }{-\frac{50}{9} }$

Reduce the fraction with -1, this eliminates the negative sign.

Simplify the complex fraction.

$\frac{\frac{19}{11} }{\frac{50}{9} } = \frac{171}{550}$

An alternative form for this fraction is 0.3109.

For the sixth equation..

Write the fraction as a division.

$\frac{3}{7}$÷$\frac{1}{10}$

To divide by a fraction, multiply by the reciprocal of that fraction.

$\frac{3}{7}$×10= $\frac{3*10}{7}$

Multiply the numbers.

$\frac{3*10}{7} = \frac{30}{7}$

Alternative form of this fraction is $4\frac{2}{7}$ or 4.285714.

Hope this helps! :)