All categories

3 years ago

True or False

1 answer:

4 0

$a,b,c-lengths\ sides\ of\ a\ triangle,\ then:\\\\a+b > c\\a+c > b\\b+c > c\\\\if\ a\leq b\leq c\ then\ a+b > c\\--------------------------\\Here:\\a=5;\ b=6;\ c=8\\\\a+b=5+6=11 > 8\\\\Answer:TRUE$

You might be interested in

The Picture and Sound electronics store has hired Kiara to work in the

olya-2409 [2.1K]

9514 1404 393

Answer:

y = 3/4x

Step-by-step explanation:

The equation of a proportional relation is ...

y = kx

The value of k can be found by dividing by x:

y/x = k

For the given values, we find k to be ...

k = y/x = (3 ft)/(4 turns) = 3/4 ft/turn

The relationship can be written ...

y = 3/4x

7 0

3 years ago

Can someone help me? Please :/

Liula [17]

I hope this picture helps you a little bit!

If you don't understand, I'll try to explain more :)

4 0

3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

Read 2 more answers

8(b+1)=-3(2+b) simply

gogolik [260]

Step-by-step explanation:

8(b+1)=-3(2+b)

8b+8=-6-3b

8b +3b = -6-8

11b = -14

b = -14/11

8 0

3 years ago

How do you solve for x: -(4 - x) = 3/4 (x - 6)?

pav-90 [236]

I honestly don’t know I am just doing this because I need to ask a question hope I helped

5 0

3 years ago