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Nastasia [14]
3 years ago
14

Reposting because I really need this fast​

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:  4.78017

Step-by-step explanation:

I think this is it

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16-3+5=? (order of operations). (show work).
a_sh-v [17]

Answer:

18

Step-by-step explanation:

When you do subtraction and addition you do it from left to right. So I did 16-3 which is 13, and I did 13+5 which is 18.

Cheers,

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3 years ago
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A recipe for 24 cookies calls for 4 tablespoons of sugar. If you make 40 cookies and use 5 tablespoons, will the cookies taste t
uranmaximum [27]

Answer:

Step-by-step explanation:

No, because they wouldn't contain the same amount of sugar per cookie  

for the first recipe - 24 cookies with 6 tablespoons  

thats 6/24 so 0.25 tablespoons of sugar per cookie  

for the second recipe - 36 cookies with 10 tablespoons  

thats 10/36 so 0.276 tablespoons per cookie  

the cookies in the second recipe would be slightly sweeter than the cookies in the first  

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A tortoise moves at a speed of 22 inches in 7 seconds. What is its average speed in feet per hour?
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3 years ago
<img src="https://tex.z-dn.net/?f=f%28t%29%20%3D%202t%20-%203%20%5C%5C%20f%287%29" id="TexFormula1" title="f(t) = 2t - 3 \\ f(7)
Ostrovityanka [42]

Answer:11

Step-by-step explanation:

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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