This is an exponential decay problem.
Using the equation Y = a *(1-rate)^time
where Y is the future value given as 12,000 and a is the starting value given as 13,000.
The rate is also given as 5%.
The equation becomes:
12,000 = 13,000(1-0.05)^x
12,000 = 13,000(0.95)^x
Divide each side by 13000:
12000/13000 = 0.95^x/13000
12/13 = 0.95^x
Use the natural log function:
x = ln(12/13) / ln(0.95)
x = 1.56 years. ( this will equal 12,000
Round to 2 years it will be less than 12000.
Answer:
The amount of wire left is 4x + 1
Step-by-step explanation:
Initially, the wire is (7x - 3) meters long.
A length of (3x - 4) meters is cut.
How much wire is left?
Initial amount subtracted by the amount that is cut. So
(7x - 3) - (3x - 4) = 7x - 3 - 3x + 4
We combine the like terms
7x - 3x - 3 + 4 = 4x + 1
The amount of wire left is 4x + 1
The answer is 8 and 1/21 in fixed fraction.
and decimal form it would be 8.047619
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.
Answer:
b=-2
Step-by-step explanation:
3√-8 = -2
-2^3 = -8