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3 years ago

Can you help, Solve for x. -2 + 3x = 2х + 6 + X

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Answer:

trick question

Step-by-step explanation:

The equation cannot be answered since if you add like terms you have 3 x on each side but different total values

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For every car you sell, you get a 6% commission. If your total sales for the month are $125, 650 , what is your commission ?

Makovka662 [10]

Answer:

=> 125,650 x 6% = $7,539

Step-by-step explanation:

4 0

3 years ago

Values of X are solutions to the equation |x| + 31=51

RideAnS [48]

Answer:

20, -20

Step-by-step explanation:

I assume you mean |x| + 31 = 51?

that means |x| + 31 - 31 = 51 - 31

==> |x| = 20

because this is absolute value

so x = 20 or -20

7 0

3 years ago

Write the scientific notation in numerals. 6.4 x 107

bezimeni [28]

Hey!

-------------------------------------------------

Writing scientific notation in numeral is solving for the equation.

Multiply 10 to 6.4 seven times.

6.4 x 10 = 64

64 x 10 = 640

640 x 10 = 6,400

6,400 x 10 = 64,000

64,000 x 10 = 640,000

640,000 x 10 = 6,400,000

6,400,000 x 10 = 64,000,000

-------------------------------------------------

Hope This Helped! Good Luck!

3 0

4 years ago

What is the solution to 3/2b + 5 < 17? Explain How.

jek_recluse [69]

<em>We subtract 5 from both sides of the inequality.</em>

<em>Multiply both sides by 2/3.</em>

<em>Therefore, the </em><em>correct option</em><em> is </em><em>alternative "A".</em>

<em>We would think that it is </em><em>option B,</em><em> but the only difference is that it changes the</em><em> direction of the sign.</em>

8 0

2 years ago

Read 2 more answers

Thirty percent of the CFA candidates have a degree in economics. A random sample of three CFA candidates is selected. What is th

Komok [63]

This is an example of a random variable that follows Bernoulli distribution.

Whenever you perform $n$ experiments, with probability $p$ of success, the provability of havin $k$ successes is

$P(X=k)=\displaystyle\binom{n}{k}p^k(1-p)^{n-k}$

In this case, you have $n=3$ (you choose a sample of 3 candidates), $p=0.3$ (30% of candidates have a degree in economics) and we want $k$ to be at least one.

One way to solve this is to consider that

$P(X\geq 1)=P(X=1)+P(X=2)+P(X=3)$

But it is much quicker to observe that

$P(X\geq 1)=1-P(X$

And we have

$P(X=0)=\displaystyle\binom{3}{0}0.3^0\cdot 0.7^{3}=1\cdot 1\cdot 0.7^3$

So, the probability that at least one of them has a degree in economics is

$1-0.7^3 = 0.657$

4 0

3 years ago