All categories

3 years ago

The figure is reflected across the x-axis and dilation by a scale factor of 3

1 answer:

5 0

Example:
Area =
4
√
3

c
m
2

Dilated by scale factor
4
≈
110.85

c
m
2

Dilated by scale factor
3
≈
997.66

c
m
2
To get from
4
√
3

c
m
2
to
997.66

c
m
2
, you would use a scale factor of

You might be interested in

Is the following sequence, Arithmetic, Geometric, or Neither?

dalvyx [7]

Answer:

neither because it's just fractions and numbers

5 0

4 years ago

The revenue each season from tickets at the theme part is represented by t(x) = 3x. The cost to pay the employees each season is

Triss [41]

Answer: The profit after 5 seasons is $239.94.

Step-by-step explanation:

Since we have given that

Revenue function is given by

$t(x)=3^x$

Cost function is given by

$r(x)=1.25^x$

So, We need to find the total profit:

As we know the formula for profit:

Profit = Revenue - Cost

$P(x)=t(x)-r(x)\\\\P(x)=3^x-1.25^x$

We need to evaluate the profit after five seasons:

$P(5)=3^5-1.25^5\\\\P(5)=\$239.94$

Hence, the profit after 5 seasons is $239.94.

5 0

4 years ago

Read 2 more answers

Does the point (273, 2) lie on the circle that is centered at the origin and contains the point (0, -4)? Explain?

valina [46]

Answer:

No, the point (273, 2) does not lie on the circle that is centered at the origin and contains the point (0, -4)

Step-by-step explanation:

The circle centered at the origin that contains the point (0,-4) has equation:

${x}^{2} + {y}^{2} = 16$

If the point (273,2) lies on this circle , then it must satisfy this equation:

${273}^{2} + {2}^{2} = 74533$

Since

$16 \ne74533$

The point does not lie on this circle.

7 0

3 years ago

Scrat the squirrel has a few nuts. When he put them in groups of 5 nuts, two nuts were left, and

iragen [17]

Answer:

The options are not shown, so i will solve this in a general way.

Let's suppose that there are N nuts

If we divide the N nuts into groups of 5, there will be a remainder of 2 nuts.

If we divide the N nuts into groups of 3, there is no remainder.

This means taht N is a multiple of 3. then we can write:

N = 3*k

where k is a random integer.

Now, we know that when we divide N by 5, there is a remainder of 2 nuts, this means that N is equal to a multiple of 5 plus 2, then we can write:

N = 5*j + 2

where j is a random integer.

Now we only need to find a pair of k and j (both positive integers) such that:

3*k = 5*j + 2

We can rewrite this as:

k = (5/3)*j + (2/3)

Now we could just input different values of j, and see if k is also an integer:

j = 2

k = (5/3)*2 + 2/3 = 10/3 + 2/3 = 12/3 = 4

Then the pair j = 2, k = 4 is a possible solution.

N = 3*k = 3*4 = 12

N = 5*j + 2 = 5*2 + 2 = 12

From this we can conclude that N = 12, so Scrat has 12 nuts.

Now with the equation

k = (5/3)*j + (2/3)

We can find other possible combinations of j and k, that will give different values for N.

for example, if j = 5:

k = (5/3)*5 + 2/3 = 25/3 + 2/3 = 27/3 = 9

Then the pair j = 5, k = 9 is also a possible solution:

N = 3*k = 3*9 = 27

N = 5*j + 2 = 5*5 + 2 = 27

In this case, Scrat has 27 nuts.

5 0

3 years ago

I NEED HELP ASAP!!!!

chubhunter [2.5K]

Answer:

bring the 2 1/2 infront of the positive 2 but in between the 2 and three. bring the 3/8 behind the negitive one but on the third smallest line. bring the -7/8 behind the positive 1 but on the 7th smallest line. bring the -2 1/2 between the negitive three and two.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers