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3 years ago

The figure is reflected across the x-axis and dilation by a scale factor of 3

1 answer:

5 0

Example:
Area =
4
√
3

c
m
2

Dilated by scale factor
4
≈
110.85

c
m
2

Dilated by scale factor
3
≈
997.66

c
m
2
To get from
4
√
3

c
m
2
to
997.66

c
m
2
, you would use a scale factor of

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The Australian sheep dog is a breed renowned for its intelligence and work ethic. It is estimated that 45% of adult Australian s

ArbitrLikvidat [17]

Answer:

Probability of more than 9 adult Australian sheep dogs out of 12 weighing 65 lb or more

P(X > 9) = 0.00788

Step-by-step explanation:

The only assumption required for the question is that all 12 adult dogs sampled must all be Australian sheep dogs.

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of adult dogs to be sampled = 12

x = Number of successes required = number of dogs that weigh 65 lb or more

= more than 9; >9

p = probability of success = probability of a dog weighing 65 lb or more = 0.45

q = probability of failure = probability of a dog NOT weighing 65 lb or more = 1 - 0.45 = 0.55

P(X > 9) = P(X=10) + P(X=11) + P(X=12)

Solving each of these probabilities, using the binomial distribution formula

P(X = x) = ¹²Cₓ (0.45)ˣ (0.55)¹²⁻ˣ with x = 10, 11 and 12

P(X > 9) = P(X=10) + P(X=11) + P(X=12)

= 0.00679820806 + 0.00101130368 + 0.00006895252

= 0.00787846427

= 0.00788 to 3 s.f

Hope this Helps!!!

3 0

3 years ago

Read 2 more answers

Find the volume.<br> 15 points

Anton [14]

Answer:

the volume is 196

Step-by-step explanation:

17x8=136

6x10=60

136+60=196

3 0

3 years ago

2x+7x+x in simplest form

sergeinik [125]

Answer:

9x + x

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg

balu736 [363]

<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles$

Now we need to find length of race

$\texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles$