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monitta
3 years ago
6

Find the radius to which the sun must be compressed for it to become a black hole.

Physics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

2950 m

Explanation:

The radius to which the sun must be compressed to become a black hole is equal to its Schwarzschild radius, which is given by the formula:

r=\frac{2GM}{c^2}

where

G is the gravitational constant

M is the mass of the star

c is the speed of light

For the Sun, its mass is

M=1.99\cdot 10^{30}kg

Therefore, its Schwarzschild radius is

r=\frac{2(6.67\cdot 10^{-11}Nm^2kg^{-2}(1.99\cdot 10^{30} kg)}{(3\cdot 10^8 m/s)^2}=2950 m

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Answer:

10 newtons

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The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl
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<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

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<h3>1)</h3>

Find the vertical and horizontal components of the two forces

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vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

                        = 0

<h3>2)</h3>

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

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4 years ago
In a Rutherford scattering experiment, an alpha particle is accelerated toward a stationary silver nucleus. If the closest appro
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Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,

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K = \frac{9\times10^{9}\times{1.6}\times10^{-19}\times{1.6}\times10^{-19}\times2\times47}{22.9\times10^{-15} }

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4 years ago
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