Ask question

Ask question

All categories

White raven [17]

2 years ago

8

An object is moving across a surface, but it is not gain or lose speed. Which best describes the objects force?

2 answers:

lina2011 [118]2 years ago

8 0

An object is moving across a surface, but it does not gain or lose speed. Which best describes the object's force?

The net force is zero.

Hope this helps!

raketka [301]2 years ago

3 0

Answer:

Gravity. An object is moving across a surface, but it does not gain or lose speed.

Explanation:

The basic idea. Physicists see gravity as one of the four fundamental forces that govern the universe, alongside electromagnetism and the strong and weak nuclear forces.

Hope it helps! Brainliest?

You might be interested in

Why is it that the two possible faults with inductors are short circuit and open circuit?

lukranit [14]

These are the most common type of faults not just inductors but also with other elements too like resistors,transformers, generators etc.
open circuit fault means the flow of current is disrupted some how in the circuit and the circuit stops operating. and for short circuit fault the current in the system will be pretty high and this short circuit current or fault current will always run back to the fault location, if the inductor got short circuited somehow then the fault current will only run through it because it will then provide a very low impedence path

5 0

3 years ago

A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction

Alja [10]

A) 1.55

The speed of light in a medium is given by:

$v=\frac{c}{n}$

where

$c=3\cdot 10^8 m/s$ is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

$v=1.94\cdot 10^8 m/s$

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

$n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55$

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda$ is the wavelenght in quartz

$\lambda_0$ is the wavelength in air

n is the refractive index

For the light in this problem, we have

$\lambda=355 nm\\n=1.55$

Therefore, we can re-arrange the equation to find $\lambda_0$ , the wavelength in air:

$\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm$

4 0

3 years ago

What happens to helium balloons when you let them go?

Ber [7]

They will rise to the 2nd layer of the atmosphere where the temperature decreases by a lot and then they will blow up

8 0

3 years ago

Read 2 more answers

Voltage can be provided by

kodGreya [7K]

All of these can provide voltage. a battery is a generator, and plugging in to an electrical outlet is just like your phone charger or TV..

5 0

2 years ago

A hawk flying at 13 m/s at an altitude of 156 m accidentally drops its prey. The parabolic trajectory of the falling prey is des

Anvisha [2.4K]

Answer:

The distance traveled will be 156.0 m

Explanation:

Please, see the attached figure 1 for a description of the problem.

The distance traveled by the prey is the magnitude of the vector "r" (see figure).

If the components of "r" are "rx" (horizontal component) and "ry" (vertical component), its magnitude will be:

$|r| =\sqrt{(rx)^{2} + (ry)^{2}}$

We already know the vertical component of r, ry, because the prey falls from an altitude of 156 m (see figure). Then ry = 156 m

To find the value of rx we will use the function that describes the trajectory of the prey (see figure 2):

y = -39 · x² + 156

When the prey hits the ground, the height is 0 (y = 0). rx will be the value of x for which y = 0.

0 = -39 · x² + 156

-156/-39 = x²

x = 2.0 m

Then r = (2.0 m, -156.0 m)

The distance traveled will be:

$|r| =\sqrt{(2 m)^{2} + (156 m)^{2}} = 156.0 m$

8 0

2 years ago