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White raven [17]
3 years ago
8

An object is moving across a surface, but it is not gain or lose speed. Which best describes the objects force?

Physics
2 answers:
lina2011 [118]3 years ago
8 0
An object is moving across a surface, but it does not gain or lose speed. Which best describes the object's force?

The net force is zero.


Hope this helps!
raketka [301]3 years ago
3 0

Answer:

Gravity. An object is moving across a surface, but it does not gain or lose speed.

Explanation:

The basic idea. Physicists see gravity as one of the four fundamental forces that govern the universe, alongside electromagnetism and the strong and weak nuclear forces.

Hope it helps! Brainliest?

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Which formula correctly shows how to calculat the time taken, given the average velocity and the displacement
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We're so good here on Brainly, we can answer it
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     Time = (displacement) / (magnitude of average velocity) .
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3 years ago
You can tell from reading this passage that -
Romashka-Z-Leto [24]

Answer: B or "diamonds are rare,valuable gems".

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3 years ago
A wave of infrared light has a speed of 6m/s and a wave length of 12 m. What is the frequency of this wave?
erastovalidia [21]
Frequency = speed / wavelength

(6 m/s) / (12 m) = 0.5 Hz.

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6 0
3 years ago
Which of the following statements is correct?
Dafna11 [192]
These are the correct solutions:

It is 11 a.m. in the Eastern Time Zone; therefore, it is 8 a.m. in the Pacific Time Zone. (3 hrs behind)

It is 3 p.m. in the Central Time Zone; therefore, 2 p.m. in the Mountain Time Zone. (1 hr behind)

It is 6 p.m. in the Pacific Time Zone; therefore, it is 4 p.m in Hawaii. (2 or 3 hours behind depending on time of year)

It is 6 p.m. in Hawaii; therefore, it is 11 p.m. in the Eastern Time Zone (5 or 6 hours behind depending on time of year).

It is 3 p.m. in Hawaii; therefore, it is 6 p.m. in the Mountain Time Zone (3 or 4 hours behind depending on time of year).
6 0
3 years ago
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
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