Answer:
f=-1380N
Explanation:
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds
.the concluding part to the question should be
What is the impact force (impulse) on the board?
solution
from the Newton's second law of motion which states that
the rate of change in momentum is directly proportional to the force applied
f=m(v-u)/t
f=0.3(0-23.3)/0.005
f=-1380N
f=force impact
m=mass of the karates master's hand
t=time for the impact
v=0m/s final velocity
u=initial velocity
Acceleration, a = (v - u) / t
Initial Velocity, u = 30 m/s
Final Velocity, v = 23 m/s
time t = 2.00 seconds
a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2
So the acceleration is negative, which means it is a deceleration of 3.5 m/s2.
We would have to use wind or another source
06758 m
Explanation:
it is correct because that is what
