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Nimfa-mama [501]
3 years ago
13

When the net forces equal 0 N, they are which of the following? A. Balanced B. Unbalanced C. A push D. A pull

Physics
1 answer:
kvv77 [185]3 years ago
5 0
When the net forces equal 0 Newtons, they are a balanced force.
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If the net force on an object is in a negative direction, what will the direction of the resulting acceleration be?
Verdich [7]
Newton's 2nd law says:          Force = (mass) x (acceleration) .

I wrote Force and acceleration in bold letters because
they're both vectors ... they have size and direction.

The equation is saying that the Force and the acceleration
are both in the same direction. 
5 0
3 years ago
Two identical satellites are in orbit about the earth. One orbit has a radius r and the other 2r. The centripetal force on the s
velikii [3]

Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2  = 2r

Centripetal force is given by

F= \frac{mv^{2}}{r}

Where v be the orbital velocity, which is given by

v=\sqrt{gr}

So, the centripetal force is given by

F= \frac{mgr}}{r}}=mg

where, g bet the acceleration due to gravity

g=\frac{GM}{r^{2}}

So, the centripetal force

F= \frac{GMm}}{r^{2}}}

Gravitational force on the satellite having larger orbit

F= \frac{GMm}{4r^{2}} .... (1)

Gravitational force on the satellite having smaller orbit

F'= \frac{GMm}{r^{2}} .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0
3 years ago
Humans protect themselves from natural disasters by all of the following except
jeyben [28]
I'm pretty sure it's sunscreen
4 0
3 years ago
Question: How is the energy in the food we eat an example of chemical potential energy?
Elanso [62]

Answer: D

Explanation: The chemical bonds in the food store energy that is released when we eat it.

3 0
3 years ago
a ship A , steaming in a direction 030° with a steady 12 km/h, sight a ship B. The velocity of B relative to A is 10km/h in a di
pickupchik [31]

Answer: 11 km/h at 339° compass

Explanation:

A sees B moving south at 0 km/h

A is moving north at 12cos30 = 10.392 km/h

Therefore B must be moving north at 10.392 k/h

A is moving east at 12sin30 = 6 km/h

B appears to be moving west at 10 km/h

Therefore B must be moving west at 10 - 6 = 4 km/h

B is moving v = √(4² + 10.392²) = 11.135... 11 km/h

θ = arctan( -4 / 10.392) = -21.05 = 339°

8 0
3 years ago
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