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cluponka [151]
3 years ago
6

A copper block (20°C) is placed in contact with a lead block (30°C), which is already in contact with an iron block (70°C). What

will happen in this situation? Heat will flow from the copper to the lead and from the iron to the lead until the temperatures are equal. Heat will flow from the lead to the copper and to the iron until the temperatures are equal. Heat will flow from the iron to the lead and from the lead to the copper until the temperatures are equal. Heat will flow from the copper to the lead to the iron until the temperatures are equal.
Chemistry
1 answer:
dlinn [17]3 years ago
8 0

Answer:

The heat flows from iron block to lead block then it flows from lead block to iron block until the temperature of three blocks are equal.

Explanation:

Given data

Temperature of the copper block = 20 °c

Temperature of the lead block = 30 °c

Temperature of the iron block = 70 °c

We know that according to law of thermodynamics heat always flows from higher temperature body to lower temperature body Until the temperature of all bodies becomes equal.

Therefore in the given problem the heat flows from iron block to lead block then it flows from lead block to iron block until the temperature of three blocks are equal.

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Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

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10 g / 12 g/m = 0.83 moles C

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0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

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The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

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