These days, scientists all over the world use a standard system of measurements. It's the SI or metric system.
What about scientists in the United States, Liberia, and Burma ? These three countries are the only ones in the world that haven't adopted the metric system. What do THEY do ?Easy. When scientists in those countries are off work, they use the inches, yards, feet, quarts, miles and gallons that everybody around them is using. But when they go to work, they use the same metric system that everyone else in the world is using.
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IF THE FIRST ONE DOESN'T WORK TRY THE SECOND
1. They use the same measuring system (metric)2. Clearly and properly collect and record data, recording the procedure and results3. Releasing the data into the public, letting everyone have access to it
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Answer:
Explanation:
Hello,
In this case, given the 0.0990 moles of the salt are soluble in 1.00 L of water only, we can infer that the molar solubility is 0.099 M. Next, since the dissociation of the salt is:
The concentrations of the A and B ions in the solution are:
![[A]=0.099 \frac{molAB_3}{L}*\frac{1molA}{1molAB_3} =0.0099M](https://tex.z-dn.net/?f=%5BA%5D%3D0.099%20%5Cfrac%7BmolAB_3%7D%7BL%7D%2A%5Cfrac%7B1molA%7D%7B1molAB_3%7D%20%20%3D0.0099M)
![[B]=0.099 \frac{molAB_3}{L}*\frac{3molB}{1molAB_3} =0.000.297M](https://tex.z-dn.net/?f=%5BB%5D%3D0.099%20%5Cfrac%7BmolAB_3%7D%7BL%7D%2A%5Cfrac%7B3molB%7D%7B1molAB_3%7D%20%20%3D0.000.297M)
Then, as the solubility product is defined as:
![Ksp=[A][B]^3](https://tex.z-dn.net/?f=Ksp%3D%5BA%5D%5BB%5D%5E3)
Due to the given dissociation, it turns out:
![Ksp=[0.099M][0.297M]^3\\\\Ksp=2.59x10^{-3}](https://tex.z-dn.net/?f=Ksp%3D%5B0.099M%5D%5B0.297M%5D%5E3%5C%5C%5C%5CKsp%3D2.59x10%5E%7B-3%7D)
Regards.
Answer:
1=4
2=2
3=hydrogen bonding
4=SO2 is reduced to Sulphur
Explanation:
<h2>I am trying my best okay.</h2>
<span>1) </span><span>Deduce
the two masses and see the amount of water was driven off when heated: </span><span>
<span>5.03 g -
4.23 g = 0.8 g H2O given off </span>
<span>2) Change
mass from grams to moles of H2O: </span>
<span>0.8 g H2O
/ 18 g H2O in 1 mole = 0.044 mol H2O </span>
<span>3) Change
left over mass to moles of BaCl2 .</span></span>
<span>
<span>4.23 g
BaCl2 / 207 g BaCl2 in 1 mol = 0.021 mol BaCl2 </span>
<span>4)Find
the ratio of mol H2O to mol BaCl2: </span>
<span>0.044 mol
H2O : 0.021 mol BaCl2 </span>
<span>5) The
resulting ratio is 2:1 so two H2O for each BaCl2, thus, the hydrate was named: </span>
<span>Barium
chloride di-hydrate</span></span>
