Answer:
48,58
Step-by-step explanation:
Let The speed of the west bound train be x
Let the east bound train be x+10
The speeds can be calculated as follows
2(2x+10)= 232
4x + 40= 232
4x= 232-40
4x= 192
x= 192/4
= 48
Hence the speedof the west bound train is 48
The speed of the east bound train is 48+10
= 58
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
The answer is C
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Answer:
=16+9=25
Step-by-step explanation:
Answer:
It is 
Step-by-step explanation:
the four is multiplied 5 times
