The height of the isosceles triangle is 8.49 inches.
<h3>
How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
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The length of the smaller leg is 3.79
<h3>How to determine the length of the smaller leg?</h3>
Represent the smaller leg with x.
So, we have:
-- Pythagoras theorem
This gives
2x^2 = 144/5
Divide by 2
x^2 = 72/5
This gives
x^2 = 14.4
Take the square root
x = 3.79
Hence, the length of the smaller leg is 3.79
Read more about right triangles at
brainly.com/question/6322314
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H represents the number of hours:
10h + 40
(40 represents, well $40)
Answer:
What the hell AC is not given so you can't find the Perimeter
Step-by-step explanation:
x+10=0
x=-10
AB=x+5
AB=-5
BC=x-2
BC=-12
Area of ABC = 30cm2
<u>Perimeter of ABC = AB+BC+</u><u>AC</u>
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I can’t see the photo I am really sorry but I don’t care
