Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
Step-by-step explanation:
He should buy 32 feet of fencing. I got 32 by just finding the perimeter or in other words adding 10+10+6+6 which equal 32. You would NOT do area or 10×6 because that would include that land within the fenced area and who wants 60 feet of fencing that you can't put anything in?
Good luck, hope that helped.
Answer:
The scale factor is 3.
Step-by-step explanation:
Let the origin O(0,0) is the reference point and the coordinates of the point A are given by (3,-6).
Therefore, the distance OA is given by 
units.
Again, the coordinates of point A' are (1,-2).
Therefore, the distance OA' is given by 
units.
Hence, the scale factor is 
. (Answer)
