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lesya692 [45]
3 years ago
5

A baseball is hit and its height is given by h = 29.4t – 4. 9t^2, where h is the

Mathematics
2 answers:
ioda3 years ago
4 0

Answer:

44.1m

Step-by-step explanation:

we are given a quadratic function which represents the height and time of a baseball

\displaystyle h = 29.4t - 4.9 {t}^{2}

we want to figure out maximum height of

the baseball

since the given function is a quadratic function so we have a parabola

which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)

to do so we can use some special formulas

recall that,

\displaystyle \rm t= \frac{ - b}{  2a}

\displaystyle H_{\text{max}}=f(t)

notice that, our given function is not in standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

let's make it so

\displaystyle h =  - 4.9 {t}^{2}  + 29.4t

therefore we got

our <em>a</em> is -4.9 and <em>b </em>is 29.4

so substitute:

\displaystyle\rm t=  \frac{ -( 29.4)}{  2 \cdot - 4.9}

remove parentheses and change its sign:

\displaystyle\rm t=  \frac{ -29.4}{  2 \cdot - 4.9}

simplify multiplication:

\displaystyle\rm t=  \frac{ -29.4}{  - 9.8}

simplify division:

\displaystyle  \: t  = 3

so we have figured out the time when the baseball will reach the maximum height

now we have to figure out the height

to do so

substitute the got value of time to our given function

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot {3}^2

simplify square:

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot 9

simplify mutilation:

\displaystyle H_{\text{max}}=88.2-44.1

simplify substraction:

\displaystyle H_{\text{max}}=44.1

hence,

the maximum height of the baseball is 44.1 metres

Alika [10]3 years ago
3 0

Answer:

Solution given:

height

h=29.4t – 4.9t²

differentiating each term with respect to time (t)

\frac{d'(h)}{d(t)}=\frac{d(29.4t – 4.9t²)}{d(t)}

\frac{d'(h)}{d'(t)}=29.4-9.8t

again second derivative

\frac{d''(h)}{d"(t)}=-9.8

for maximum, minimum

first derivative =0

29.4-9.8t=0

t=\frac{29.4}{9.8}=3

So it attains maximum height at t=3

so

maximum height=29.4×3-4.9×3² =44.1meters

So.

<em><u>maximum height of the basketball is 44.1meters</u></em>

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Answer:

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7 0
2 years ago
AYUDAAA porfavorrrr primera urna 6 bolas verdes y 3 rojas segunda urna 3 verdes, 3 blancas y 3 rojas tercera urna 6 verdes, 1 bl
marin [14]

We have the following information:

first urn: 6 green balls and 3 red ones

total: 6 + 3 = 9

second urn: 3 green, 3 white and 3 red

total: 3 + 3 + 3 = 9

third urn: 6 green, 1 white and 2 red

total: 6 + 1 + 2 = 9

a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.

b) probability of drawing a green, red and white ball.

first urn:

green = 6/9 = 66.66%

red = 3/9 = 33.33%

white = 0/9 = 0%

second urn:

green = 3/9 = 33.33%

red = 3/9 = 33.33%

white = 3/9 = 33.33%

third urn:

green = 6/9 = 66.66%

red = 2/9 = 22.22%

white = 1/9 = 11.11%

c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%

d) without a green ball, the third ballot box would look like this:

5 green balls, 2 red balls and 1 white ball, with a total of 8.

The probability of drawing would be:

green = 5/8 = 62.5%

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7 0
3 years ago
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul
sesenic [268]

The expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,


C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}


now put the value in the formula.

5 = \sqrt{(x-6^2)+(y - 5)^2}

Thus, expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.


Learn more about equation here:

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4 0
1 year ago
Which of the following is not one of the 8th roots of unity?
Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1.  Since z=1=1+0\cdot i, then

Rez=1,\\ \\Im z=0

and

|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.

This gives you \varphi=0.

Thus,

z=1\cdot(\cos 0+i\sin 0).

2. The 8th roots can be calculated using following formula:

\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.

Now

at k=0,  z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;

at k=1,  z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=2,  z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;

at k=3,  z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=4,  z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;

at k=5,  z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

at k=6,  z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;

at k=7,  z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

The 8th roots are

\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.

Option C is icncorrect.

5 0
3 years ago
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Answer:

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