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uranmaximum [27]
3 years ago
7

Solve the proportion for k k+7 = 4k+15 29= 21

Mathematics
2 answers:
OleMash [197]3 years ago
5 0

Answer:

k=3/8

Step-by-step explanation:

k+7 = 4k+15

-k       -k

-------------------

7=3k +15

-15    -15

------------

8=3k

----------

3

k=3/8

mafiozo [28]3 years ago
4 0

Answer:

k+7

k-7

or k+7/k-7

Step-by-step explanation:

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Snowcat [4.5K]
Given a group of n object. We want to make a selection of k objects out of the n object. This can be done in 

C(n, k) many ways, where C(n, k)= \frac{n!}{k!(n-k)!},

where k!=1*2*3*...(k-1)*k


Thus, we can do the selection of 3 cd's out of 5, in C(5,3) many ways, 

where 

C(5, 3)= \frac{5!}{3!2!}= \frac{5*4*3*2*1}{3*2*1*2*1}= \frac{5*4}{2}=10

Answer: 10
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3 years ago
Help me answer these PLEASE ASAP
Hoochie [10]

Answer:

Answered below

Step-by-step explanation:

<u>Sheet 1: Question 3</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠LPN = ∠OPM

7 + 13x = -20 + 16x

27 = 3x

x = 9

<u>Sheet 1: Question 4</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠ABD = ∠EBC

2x + 20 = 3x + 15

-x = -5

x = 5

<u>Sheet 1: Question 5</u>

<u>Step 1: Find the value of x</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠SOP = ∠ROQ

5x = 4x + 10

x = 10

<u>Step 2: Find angles</u>

Angle SOP = 5x = 5(10) = 50°

Angle ROQ = 50° <em>(because it is vertically opposite to angle SOP)</em>

Angle SOR = 180 - 50 <em>(because all angles on a straight line are equal to 180°)</em>

Angle SOR = 130°

Angle POQ = 130° <em>(because it is vertically opposite to angle SOR)</em>

<u>Sheet 1: Question 6</u>

Angle 1 = 72° <em>(because vertically opposite angles)</em>

∠4 + ∠1 + 41 = 180° <em>(because all angles on a straight line are equal to 180°)</em>

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° <em>(because vertically opposite angles)</em>

∠2 = 67° <em>(because vertically opposite angles)</em>

<u>Sheet 2: Question 3</u>

Step 1: Find the value of x

<em>Sum of complementary angles is equal to 90°</em>

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

x = 7

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 7x + 4

7(7) + 4

Angle A = 53°

Angle B: 4x + 9

4(7) + 9

Angle B = 37°

<u>Sheet 3: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>Sum of supplementary angles is equal to 180°.</em>

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 3x - 7

3(37)-7

Angle A = 104°

Angle B: 2x + 2

2(37) + 2

Angle B = 76°

<u>Sheet 3: Question 4</u>

<em>Sum of supplementary angles is equal to 180°.</em>

<u>Step 1: Find x</u>

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

36x - 8 +12x - 40 = 180 x 4

48x - 48 = 720

48x = 768

x = 16

<em>Step 2: Find both angles with the help of x</em>

Angle 1: 1/4(36x-8)

1/4[36(16)-8] = 568/4

Angle 1 = 142°

Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

Angle 2 = 38°

<u>Sheet 4: Question 1</u>

<em>All angles on a straight line are equal to 180°</em>

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

<u>Sheet 4: Question 2</u>

Linear pair 1: 5 and 7 <em>(because both angles are on a straight line and are equal to 180°)</em>

Linear pair 2: 6 and 8<em> (because both angles are on a straight line and are equal to 180°)</em>

<u>Sheet 4: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>All angles on a straight line are equal to 180° or linear pairs are equal to 180°</em>

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

x = 150/12

x = 12.5

<em>Step 2: Find angles using the value of x</em>

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

<u>Sheet 4: Question 4</u>

<em>Linear pairs are equal to 180°.</em>

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

<em>Take LCM = 6</em>

[2(27x-6) + 3(6x-20)]/6 = 180

54x - 12 + 18x - 60 = 1080

72x - 72 = 1080

72x = 1152

x = 16

!!

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3 years ago
Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.480
Lilit [14]

Step-by-step explanation:

The nth term of a geometric progression can be determined by using the formula:

Tn=arn−1

where: a = first term and r = common ratio

Substitute the given values of first term and common ratio into the formula:

Tn=arn−1

T5=(40)(0.5)5−1

T5=(40)(0.5)4

T5=(40)(0.0625)

T5=2.5

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3 years ago
What value of x gives y= -2 ?
IrinaVladis [17]
The value of x = 0 which is none
8 0
3 years ago
Divide the fraction and then simplify to its lowest form.
Andre45 [30]

Answer:

2/5

Step-by-step explanation:

3/10÷3/4

3/10×4/3

4/10

2/5

3 0
3 years ago
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