11/8 or 13/8 is the answer.
AB = 6 cm, AC = 12 cm, CD = ?
In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.
Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°
In order to find ∠BCA, use the law of sines:
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA
Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°
Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°
In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.
12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
A function is odd if:
f ( - x ) = - f ( x )
A ) f ( - x )= 0.8 ( - x ) ^3 = - 0.8 x^3 = - f ( x )
Answer: A ) f ( x ) = 0.8 x^3 is an odd function.
Functions B ) and C ) are even and D) is neither even nor odd.
Answer:
∠BAC = 105°
Step-by-step explanation:
2(5x) = 9x+21
10x = 9x+21
reduce:
x = 21
∠BAC = 5x = 105°
Answer:
m<1= 128 degree ( being alternate angle)
m<2
= 180degree - 128degree ( being cointerior angle)
=52degree
m<3= 138degree being corresponding angle)