The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄
From the question given above, the following data were obtained:
Mass of Cu = 0.64 g
Mass S = 0.32 g
Mass of O = 0.64 g
<h3>Empirical formula =? </h3>
The empirical formula of the compound can be obtained as follow:
Cu = 0.64 g
S= 0.32 g
O = 0.64 g
Divide by their molar mass
Cu = 0.64 / 63.5 = 0.01
S= 0.32 / 32 = 0.01
O = 0.64 / 16 = 0.04
Divide by the smallest
Cu = 0.01 / 0.01 = 1
S= 0.01 / 0.01 = 1
O = 0.04 / 0.01 = 4
Therefore, the empirical formula of the compound is CuSO₄
Learn more: brainly.com/question/13086832
The specific heat of silver is calculated as below
Q(heat) = M(mass) xC(specific heat capacity)
Q= 42.8 j/c
M=181 g
C=?
by making C the subject of the formula
C= Q/M
C= 42.8 j/c/181 g =0.236j/g/c
Answer: 94.07%
Explanation:
Percentage yield can be calculated by the formula
%yield = Experimental yield/Theoretical yield x100
Experimental yield = 7.93g
Theoretical yield = 8.43
%yield = Experimental yield/Theoretical yield x100
%yield = 7.93/8.43 x 100 = 94.07%
Eventually the oceanic plate is subducted under the continental plate due to the high density of the oceanic plate.
Both — rate :) hope this helps