Question

1.6g of a compound were found to contain 0.64g of copper, 0.32g of sulfur and 0.64g of oxygen. Calculate it's empirical formula.

Answer 1

The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄

From the question given above, the following data were obtained:

Mass of Cu = 0.64 g

Mass S = 0.32 g

Mass of O = 0.64 g

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

Cu = 0.64 g

S= 0.32 g

O = 0.64 g

Divide by their molar mass

Cu = 0.64 / 63.5 = 0.01

S= 0.32 / 32 = 0.01

O = 0.64 / 16 = 0.04

Divide by the smallest

Cu = 0.01 / 0.01 = 1

S= 0.01 / 0.01 = 1

O = 0.04 / 0.01 = 4

Therefore, the empirical formula of the compound is CuSO₄

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