Question

A specific park is rectangular-shaped and has a 3 mile-perimeter. The length is 4 times the width. What are the dimensions of the park?​

Answer 1

Answer:

The length of the rectangular park is $1.2\ mi$ and the width of the rectangular park is $0.3\ mi$

Step-by-step explanation:

Let

x ----> the length of the rectangular park

y ---> the width of the rectangular park

we know that

The perimeter is equal to

$P=2(x+y)$

$P=3\ mi$

so

$3=2(x+y)$ -----> equation A

$x=4y$ ----> equation B

substitute equation B in equation A and solve for y

$3=2(4y+y)$

$3=10y$

$y=0.3\ mi$

Find the value of x

$x=4(0.3)=1.2\ mi$

therefore

The length of the rectangular park is $1.2\ mi$ and the width of the rectangular park is $0.3\ mi$