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Len [333]
3 years ago
5

Can someone please help me with this

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

value of k

k= 1.380 649. 10^-23 J / K or k= 8.617 333 262 . 10^-5 eV / K

Step-by-step explanation:

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What is the slope intercept form for x+3y=0
Norma-Jean [14]

Answer:

y = -1/3 x

Step-by-step explanation:

what is the slope intercept form for x+3y=0

Slope intercept form solves for y:

x + 3y = 0

subtract x from both sides:

x + 3y - x = 0 - x

3y = -x

divide both sides by 3:

3y/3 = -x/3

y = -1/3 x

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hannah's school hosted a book donation. there are 150 students at her school, and they donated b books! hannah donated 3 times a
MArishka [77]
3b=150 should be the answer.
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3 years ago
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Describe a real-world situation that the graph could represent. Then describe the possible values for each variable
Alex777 [14]

Answer:

Speed=distance/time i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

Speed=distance/time

So, if we take distance on y axis and time on x axis with points as (distance,time)

(0,0) ==> v=0/0=0

(1,2) ==> v=1/2=0.5

(2,2) ==> v=2/2=1

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

8 0
3 years ago
Name the relationship
Ivanshal [37]

Answer:

A vertical angle!

Step-by-step explanation:

Vertical angles sit across from each other.

4 0
3 years ago
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Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
4 years ago
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