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3 years ago

Can someone please help me with this

Mathematics

1 answer:

monitta3 years ago

8 0

Answer:

value of k

k= 1.380 649. 10^-23 J / K or k= 8.617 333 262 . 10^-5 eV / K

Step-by-step explanation:

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What time is 10 minutes before 8:00 in the morning? *

strojnjashka [21]

Answer: 7:50 AM

Step-by-step explanation:

The clock goes to 60 minutes so if you subtract 10 from 8:00 AM

It will start at 7:60

7:60-10 is 7:50

6 0

3 years ago

Read 2 more answers

A cylinder has radius 2.5 cm and lateral area 20 pi cm^2. What is the surface area of the cylinder in terms of pi?

Novosadov [1.4K]

This is the concept of areas of solid materials; the surface area of the cylinder whose radius is 2.5 cm and lateral area is 20 pi cm^2 will be: Surface area of cylinder is given by:
SA=(area of cyclic sides)+(lateral area)
SA=2πr^2+πrl
Area of the cyclic sides will be:
Area=2πr^2
=2*π*2.5^2
=12.5π cm^2
The lateral area is given by:
Area=20π cm^2
Therefore the surface area of cylinder will be:
SA=(12.5π+20π) cm^2
SA=32.5π cm^2
The answer is 32.5π cm^2

4 0

3 years ago

What is a radius of a circle given by the equation x²-2x+8y-47=0

Zolol [24]

First, we are going to rewrite it as a parabola equation.
Rewrite.
$8y=-x^2+2x+47$
Divide by 8.
$y=-\frac{x^2}{8}+\frac{x}{4}+\frac{47}{8}$
Factor out coefficient.
$y=-\frac{1}{8}\left(x^2-2x\right)+\frac{47}{8}$
Then, we are going to convert x into square form.
$y=-\frac{1}{8}\left(x^2-2x+1\right)+\frac{1}{8}\cdot \:1+\frac{47}{8}$
Convert the whole expression into square form.
$y=-\frac{1}{8}\left(x-1\right)^2+\frac{1}{8}\cdot \:1+\frac{47}{8}$
Simplify.
$y=-\frac{1}{8}\left(x-1\right)^2+6$
Subtract 6 from both sides.
$y-6=-\frac{1}{8}\left(x-1\right)^2$
Divide by coefficient.
$-8\left(y-6\right)=\left(x-1\right)^2$
Rewrite in standard form.
$4\left(-2\right)\left(y-6\right)=\left(x-1\right)^2$

The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive.
Have a nice day! :)

7 0

3 years ago

Read 2 more answers

I cant figure this out

aksik [14]

Answer:

Step-by-step explanation:

660

4 0

3 years ago

How do you do this problem?

zhenek [66]

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0. So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

5 0

3 years ago