Answer:
a. 215.6 in^3
b. 1.51 lb
Step-by-step explanation:
The area of each hand grip hole is that of a circle of radius 0.6 in together with a rectangle 2 in long and 1.2 in wide. So, that area is ...
π·(0.6 in)^2 + (2 in)(1.2 in) = (0.36π +2.4) in^2
The area of the kickboard before the hand grip holes are put in is that of a semicircle of radius 5.5 in together with a rectangle 12 in long and 11 in wide. So, that area is ...
(1/2)·π·(5.5 in)^2 + (12 in)(11 in) = (15.125π +132) in^2
Taking the hand grip holes out, the top area of the board is ...
((15.125π +132) -2(0.36π +2.4)) in^2
= (14.405π + 127.2) in^2
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a. The volume is the product of the area and the thickness, so is ...
((14.405π +127.2) in^2)·(1.25 in) ≈ 215.568 in^3
__
b. The weight of the kickboard is the product of its volume and its density:
(215.568 in^3)(0.007 lb/in^3) ≈ 1.509 lb
Answer:
I'm not sure but I think it could be 1440cm³
Step-by-step explanation:
have a great rest of ur day
Answer:
is the answer
Step-by-step explanation:
Equation of the line: y = 6/5x + 1
= 5y = 6x + 5
= 6x - 5y + 5
Equation of the perpendicular line: bx - ay + k = 0
= -5x -6y + k = 0
Equation passes through (6,-6),
-5(6) -6(-6) + k = 0
-30 + 36 + k = 0
6 + k = 0
k = -6
Substituting,
-5x -6y + k = 0
-5x -6y -6 = 0
-6y = 5x + 6
(Slope-Intercept form)
516 is the dividend, 3 is the divisor, 172 would be the quotient.
3 goes into 5 once with a 2 remainder, that 2 turns into 21 because of the 1 in 516 which 3 goes into seven times with a remainder of zero turning into 6, which 3 goes into twice, making the quotient 172.
172 times 3 is 516
