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AnnyKZ [126]
2 years ago
9

On a number line, A is at 5 and B is at 50. Point X is the midpoint. Point T is 2/3 of the way from X to B. Determine the coordi

nate of point T.
Mathematics
1 answer:
Lemur [1.5K]2 years ago
6 0

Number lines are used to represent points at regular interval.

The coordinate of point T on the number line is: 46.5

Given that:

A =5

B = 50

The coordinate of X at the midpoint is:

X = \frac{B + A}{2}

So, we have:

X = \frac{50+5}{2}

X = \frac{55}{2}

X = 27.5

Point T is at 2/3 from X to B.

The coordinate of T is calculated using:

T = X + \frac 23 (B - X + 1)

So, we have:

T = 27.5 + \frac 23 (55 - 27.5 + 1)

T = 27.5 + \frac 23 (28.5)

T = 27.5 + 19

T = 46.5

<em>Hence, T is located at 46.5</em>

Read more about number lines at:

brainly.com/question/18611090

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
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Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

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Which of the following is the correct factorization of the polynomial below?
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Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)

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(2x+3y)(4x^2-6xy+9y^2) <----answer

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