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AnnyKZ [126]
2 years ago
9

On a number line, A is at 5 and B is at 50. Point X is the midpoint. Point T is 2/3 of the way from X to B. Determine the coordi

nate of point T.
Mathematics
1 answer:
Lemur [1.5K]2 years ago
6 0

Number lines are used to represent points at regular interval.

The coordinate of point T on the number line is: 46.5

Given that:

A =5

B = 50

The coordinate of X at the midpoint is:

X = \frac{B + A}{2}

So, we have:

X = \frac{50+5}{2}

X = \frac{55}{2}

X = 27.5

Point T is at 2/3 from X to B.

The coordinate of T is calculated using:

T = X + \frac 23 (B - X + 1)

So, we have:

T = 27.5 + \frac 23 (55 - 27.5 + 1)

T = 27.5 + \frac 23 (28.5)

T = 27.5 + 19

T = 46.5

<em>Hence, T is located at 46.5</em>

Read more about number lines at:

brainly.com/question/18611090

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Someone help I don't know what the diameter or radius is​
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<h3><u>Answer:</u></h3>

52.38 inch² & 261.90 inch²

<h3><u>Step-by-step explanation:</u></h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

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<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

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