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Yuki888 [10]
3 years ago
6

Please help me I suck at math!​

Mathematics
2 answers:
lisov135 [29]3 years ago
8 0

Answer:

<em>0.000008</em>

Step-by-step explanation:

Since the exponent of the scientific notation is negative, move the decimal point  6  places to the left.

<em>0.000008</em>

<em>brainliest pls</em>

jeyben [28]3 years ago
3 0
0.000008 is the answer to your question.
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Describe the nature of the roots for this equation.
kirza4 [7]

Answer:

Option D. two complex roots

Step-by-step explanation:

we know that

In a quadratic equation of the form ax^{2} +bx+c=0 the discriminant D is equal to

D=(b^{2}-4ac)

in this problem we have

3x^{2} -2x+1=0  

so

a=3\\b=-2\\c=1

substitute the values

D=(-2^{2}-4(3)(1))

D=(4-12)

D=-8

The discriminant is negative

therefore

The quadratic equation has two complex roots

5 0
3 years ago
Hello everyone, need help on this, select all the correct answers that are equivalent.
mihalych1998 [28]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

You can perform the division and look at the quotient and remainder to convert an improper fraction to a mixed number.

  23 ÷ 6 = 3 r 5   ⇒   23/6 = 3 5/6 ≠ 4 1/6

  11 ÷ 4 = 2 r 3   ⇒   11/4 = 2 3/4 ≠ 2 1/2

  35 ÷ 4 = 8 r 3   ⇒   35/4 = 8 3/4

  15 ÷ 8 = 1 r 7   ⇒   15/8 = 1 7/8

  40 ÷ 12 = 3 r 4   ⇒   40/12 = 3 4/12 = 3 1/3

5 0
3 years ago
Find the quotient.<br><br> 12a3p4 ÷ -2a2p<br><br> -6a3p5<br> -24ap3<br> -6ap3<br> 6a5p3
kap26 [50]

Step-by-step explanation:

Given

12a³p^4 / - 2a²p

= - 6* a^3 - 2 * p^4- 1

= - 6ap³

Hope it will help :)

8 0
3 years ago
Someone please help me!
andrezito [222]
The standard form of a parabole is: (y-k) = a(x-h)², Where (h , k) are the coordinates of the vertex
In the example Vertex (3,1) ,
so (y-1) = a(x-3)². (a)
Now let's calculate a. The y-intercept coordinates(0 , 10), Replace in (a) x by 0 & y by 10:
(10-1) = a(0 - 3)²
9 = 9a and a=1
<u />The equation becomes : y-1 = (x-3)², Expand (y-1) = x²-6x+9
<u />and finally y = x² - 6x +10 (ANSWER C)
6 0
3 years ago
The pre–image, A, was dilated about the origin. It was then transformed in another way to get A'.
Elenna [48]

Answer:

reflection over the x-axis

Step-by-step explanation:

i hope this helps

6 0
3 years ago
Read 2 more answers
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