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galben [10]
3 years ago
12

The transformation maps ΔABC to ΔA'B'C'. Which statement is true about the transformation?

Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0
The answer is the second option
zepelin [54]3 years ago
3 0
It is isometric because all side lengths and angle measures remained the same.

I hope this help.
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Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
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\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=\stackrel{doubled}{2b} \end{cases}\implies A=\cfrac{1}{2}(2b)(h)\implies \stackrel{\textit{twice as the original area}}{A=bh} \\\\[-0.35em] ~\dotfill

\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=\stackrel{halved}{\frac{h}{2}} \end{cases}\implies A=\cfrac{1}{2}b\left( \cfrac{h}{2} \right)\implies \stackrel{\textit{half of the original area}}{A=\cfrac{1}{2}bh\left( \cfrac{1}{2} \right)}

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4 years ago
Marks test scores for this semester were 83,80,91,74,66,95,87,72,95,97 what is the mode of his test scores
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Ok

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do u mean into bracket 61/4 raised to the power of 4???

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