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ipn [44]
3 years ago
5

8/15-1/5 For points or brainliest

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0
It’s equals 1/3 one third
Aleonysh [2.5K]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

The answer is 1/3 to find out how look at the picture above!

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Whats the slope for (-3, -4) and (-2, -10)
Dominik [7]

Answer:

-6

Step-by-step explanation:

Trust me fam

8 0
3 years ago
Read 2 more answers
An orange triangular warning sign by the side of the road has an area of 266 square inches. The base of the sign is 9 inches lon
pashok25 [27]

Answer: the base is 28 inches. The altitude is 9 inches

Step-by-step explanation:

Let h represent the altitude of the sign.

Let b represent the length if the base of the sign.

The warning sign is triangular in shape.

The formula for determining the area of a triangle is expressed as

Area = 1/2bh

The base of the sign is 9 inches longer than the altitude. This means that

b = h + 9

If the area of the sign is 266 square inches, it means that

266 = 1/2 × h(h + 9)

266 × 2 = h(h + 9)

532 = h² + 9h

h² + 9h - 532 = 0

h² + 28h - 19h - 532 = 0

h(h + 28) - 19(h + 28) = 0

h(h + 28) - 19(h + 28) = 0

(h + 28)(h - 19) = 0

h = 19 or h = - 28

Since the height cannot be negative, then h = 19

b = h + 9 = 10 + 9

b = 28

5 0
4 years ago
Which complex number has a distance of V17 from the origin on the complex plane?
Nataly_w [17]

Answer:

4-i

Step-by-step explanation:

Use the formula for the distance of a complex number from the origin on the complex plane.

\sqrt{a^2+b^2}

a+bi

4-i

\sqrt{4^2-i^2}

\sqrt{4^2+(-1)^2}=\sqrt{16+1}=\sqrt{17}

The complex number that has a distance of \sqrt{17} is 4-i.

5 0
4 years ago
How much is 6 dimes 3 nickels and 1 quarter
tankabanditka [31]

Answer:

$1.00

Step-by-step explanation:

Dimes = 10 / Nickels = 5 / Quarters = 25

6(10) + 3(5) + 1(25)

60 + 15 + 25 = 100 so that makes it $1.00

6 0
3 years ago
Helppp meeeeee please ​
Illusion [34]

Answer:

The answer is F

Step-by-step explanation:

Because I said so

3 0
2 years ago
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