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sattari [20]
3 years ago
15

During one month there Were seven days of precipitation what if there had only been three days of precipitation that money how w

ould that change the measure of center
Mathematics
1 answer:
mart [117]3 years ago
5 0
We've hit on a case where a measure of center does not provide all the information  spread or variability there is in month-to-month precipitation.  based on how busy each month has been in the past, lets managers plan

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the ratio of boy to girls in a school 1s 5:7. if there are 780 students in the school, how many boys are in the school?
kenny6666 [7]

Answer:

325 boys

Step-by-step explanation:

The ratio 5:7 represents 5+7=12 students. If we were to proportionalize this ratio to 780 students, we would multiply the ratio by 65/65 since 780/12=65.

Therefore, you have (5*65)/(7*65)=325/455 as your ratio. This means that there are 325 boys in the school

5 0
3 years ago
A trains leaves Cincinnati at 2:00 pm.A second train leaves the same station in the same direction at 4:00 pm.The second train t
kvasek [131]

Answer:

Speed of first train = 36 mph

Speed of second train =  60 mph

Step-by-step explanation:

Given:

First train leaves Cincinnati at 2:00 PM

Second train leaves same station at 4:00 PM

Speed of second train is 24 mph faster than first train.

The second train overtakes the first at 7:00 PM

To find the speeds of each train.

Solution:

First train:

Let speed of first train be = x\ mph

Time of travel between 2:00 PM to 7:00 PM = 7-2=5\ h

Distance traveled by 1st train in 5 hours in miles = Speed\times time = x\times 5 = 5x

Second train:

Then, speed of second train will be = (x+24)\ mph

Time of travel between 4:00 PM to 7:00 PM =7-4 = 3\ h

Distance traveled by second train in 3 hours in miles = Speed\times time = (x+24)\times 3=3x+72

At 7:00 PM both trains meet as the second train overtakes the first. This means the distance traveled by both the trains is same at 7:00 PM as they both leave from same stations.

Thus, we have:

5x=3x+72

Solving for x

Subtracting both sides by 3x

5x-3x=3x-3x+72

2x=72

Dividing both sides by 2.

\frac{2x}{2}=\frac{72}{2}

∴ x=36

Speed of first train = 36 mph

Speed of second train = 36+24= 60 mph

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