If triangle KMN is congruent with triangle LMN, then:
1) KM must be congruent with LM→KM=LM→
x+2y=3x-y→x+2y-x-2y=3x-y-x-2y→0=2x-3y→2x-3y=0 (1)
2) KN must be congruent with LN→KN=LN→
5x+3y=8x-7→5x+3y-5x-3y+7=8x-7-5x-3y+7→7=3x-3y→3x-3y=7 (1)
We have a system of two equations and two unkowns:
(1) 2x-3y=0
(2) 3x-3y=7
Subtracting equation (1) from equation (2)
(3x-3y)-(2x-3y)=7-0
3x-3y-2x+3y=7
x=7
Replacing x=7 in equation (1)
(1) 2x-3y=0→2(7)-3y=0→14-3y=0→
14-3y+3y=0+3y→14=3y→14/3=3y/3→14/3=y→y=14/3
The length of the hypotenuse is:
KN=5x+3y=5(7)+3(14/3)=35+14→KN=49
or
LN=8x-7=8(7)-7=56-7→LN=49
Answer: Option C. 49
Answer:15/1
Step-by-step explanation: 300 Divided by 20 is 15 and i believe that is the answer im sorry if i am wrong
Answer:
No solution
Step-by-step explanation:
-x + y = 8..............(1)
1/2x - 1/2y = 3......(2)
Multiply (2) by 2
x - y = 6 ............(3)
Adding (1) and (3)
-x + x + y - y = 8 + 3
x and y are both eliminated so no solution
9^0 its that answer because all the other number you can make a whole number.
