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2 years ago

Give the equation for the line: please someone answer this for me woth 20 points!!!!!

Mathematics

2 answers:

guapka [62]2 years ago

6 0

Answer:

y=x/4

Step-by-step explanation:

slope =y2-y1/x2-x1

=1-0/4-0=1/4

jeka57 [31]2 years ago

6 0

Answer: slope intecept form: y = 1/4x

Step-by-step explanation: first we need to find the slope:

Since we have the coordinates (0,0) and (4,1), we can find the slope, which we find 1/4. We can double check this by seeing if the next point is found +4 to the right and up 1.

We have y = 1/4x + b right now, so we need to find the y intercept, in which case is zero because it goes through the origin.

So your final answer is y = 1/4x + 0, or y = 1/4x for short.

Hope this helps!

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there is a room 7 feet x 9 feet you lay a 1-foot wide plank from corner to corner touching all 4 walls how long is the plank

Alex73 [517]

Answer:

Step-by-step explanation:

l^2=[(7-V2)/2]^2+(9-V2/2)^2=

49-7V2+2/4+81-9V2+2/4=

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131-16V2=108.4 ft

so l=V108.4≈10.4ft

5 0

3 years ago

X/4 +2 helppppp plzzz

inysia [295]

Answer:

Step-by-step explanation:

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3 years ago

Riley bought 30 festival tickets for his friends and paid $145.How much did each ticket cost?

Sladkaya [172]

Answer: $4.83

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

Given 7x + 2 ≥ 58, which number is not in the solution set?

Natasha_Volkova [10]

Answer:

i can't see the rest of the question so i don't know the answer choices but:

since x≥8

whichever choice is less than 8 is incorrect

step-by-step explanation:

i can't see the rest of the question so i don't know the answer choices but:

7x≥56

x≥8

4 0

3 years ago

Pratap puri rowed 10 miles down a river in 2 hours, but the return trip took him 2 and one half hours. Find the rate pratap can

N76 [4]

Answer:

Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.

We know that, $Speed = \frac{Distance}{Time}$

So, the speed of Pratap with the current will be: $(\frac{10}{2})miles/hour = 5$ miles/hour

and the speed of Pratap against the current will be: $(\frac{10}{2.5})miles/hour = 4$ miles/hour.

Suppose, the rate of Pratap in still water is $x$ and the rate of current is $y$ .

So, the equations will be........

$x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)$

Adding equation (1) and (2) , we will get......

$2x=9\\ \\ x=\frac{9}{2}= 4.5$

Now, plugging this $x=4.5$ into equation (1), we will get.....

$4.5+y=5\\ \\ y=5-4.5 =0.5$

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0

3 years ago

Give the equation for the line: please someone answer this for me woth 20 points!!!!!​

Give the equation for the line: please someone answer this for me woth 20 points!!!!!