Answer:
The median is also the number that is halfway into the set. To find the median, the data should be arranged in order from least to greatest. If there is an even number of items in the data set, then the median is found by taking the mean (average) of the two middlemost numbers.
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Solution :
Millimoles of hydrocyanic acid = 225 x 0.368
= 82.8
Millimoles of potassium cyanide = 225 x 0.360
= 81
Millimoles of sodium hydroxide = 51.3
Therefore,
pOH = pKb + log [salt - C / bas + C]
= 4.74 + log[82.8 - 51.3 / 81 + 51.3]
= 4.102
Therefore, pH = 9.05
Answer: STP
CaCO3 = 5 g
Convert gram to mol
100 g of CaCO3 = 1 mol
5 g of CaCO3 (n) = 5 g *(1 mol/100 g) = 0.05 mol
Gas law
PV =nRT
V = nRT/P
V = (0.05 mol * (0.08206 L atm /K mol) *273 K)/1 atm
V = 1.124 L
Explanation:
Answer:
greases
Explanation:
Ink is manufactured in two stages: first varnish (a mixture of solvent, resins and additives) is made and then pigments are mixed into it. Varnish is a clear liquid that solidifies as a thin film. It binds the pigment to the printed surface, provides the printability of the ink and wets the pigment particles. Ink made with color usually includes the following ingredients: petroleum distillate solvent, linseed oil, some form of organic pigments, and soybean oil. Inorganic pigments are not commonly used.
Additives play a critical role in the formulation and production of inks, helping to impart the necessary characteristics the ink needs, whether it is to run more smoothly on press or to protect the finished product.
However, grease is not one of the likely additives to ink hence it is not essentially used in ink production.
1. 12.992 L
2. 2.42 moles
3. 275.52 L
4. 567.844 g
<h3>Further explanation</h3>
Given
moles and volume at STP
Required
mass, volume and moles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
1. 0.58 moles ammonia :
Volume = 0.58 moles x 22.4 L = 12.992 L
2. 77.5 grams of O₂ :
Moles = 77.5 grams x (1 mol/32 grams) = 2.42
3. 12.3 mole of Bromine gas :
Volume = 12.3 mole x (22.4 L/1 mole) = 275.52 L
4. 4.8 moles iron(II)chloride :
Mass = 4.48 moles x molar mass ( 126,751 g/mol) = 567.844 g
