These are 3 assumptions that i know for a fact. Hope this helped.
1.Gas particles are continuous, rapid, random motion. They therefore possess kinetic energy, which is energy of motion.
2.There are no forces of attraction between gas particles.
3.The temperature of a gas depends on the average kinetic energy of the particles of the gas.
Answer:
ΔG° = 1022. 8 kJ
Explanation:
ΔH° = –199 kJ/mol
ΔS° = –4.1 J/K·mol
T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)
ΔG° = ?
The relationship between these varriables are;
ΔG° = ΔH° - TΔS°
ΔG° = –199 - 298 (–4.1)
ΔG° = -199 + 1221.8
ΔG° = 1022. 8 kJ
Answer:
See Explanation
Explanation:
By definition, 1 mole is the mass of substance (or, formula mass in grams) containing 1 Avogadro's Number (N₀ = 6.02 x 10²³) of particles. That is ...
1 mole of hydrogen atoms (H) = 1.00794 grams
1 mole of molecular hydrogen (H₂) = 2.01588 grams
1 mole of any substance = 1 formula weight in grams
1 mole = 1 Avogadro's Number (N₀) = 1 formula weight in grams
In the concept of 'gas laws' 1 mole of any (all) gas at STP conditions ( => 0°C & 1 atmosphere pressure) occupies 22.4 Liters & is known as the 'molar volume' of a gas at STP. If the temperature &/or pressure change the volume will not be 22.4 Liters.
For reactions whose coefficients are balanced to the lowest whole number values (i.e., no fractional coefficients) the equation is known as the 'standard reaction' and conditions are assumed to be STP and the coefficients of gas phase components indicate molar volumes. Example ...
Given N₂(g) + 3H₂(g) => 2NH₃(g) is assumed to be at 0°C; 1 Atm pressure.
Molecular Nitrogen = 1 molar volume = 22.4 Liters of N₂(g)
Molecular Hydrogen = 3 molar volumes = 3 x 22.4 Liters of H₂(g) = 67.2 Liters of H₂(g)
Molecular Ammonia = 2 molar volumes = 2 x 22.4 Liters of NH₃(g) = 44.8 Liters of NH₃
<span> Speicific heat of water is 4.2j/gm*C </span>
<span>Thus 4.2 Joules of energy is required to heat 1 gm water to 1*C. </span>
<span>or 4.2 x 30 Joules enery is required to heat 1x30 gm water by 1*C </span>
<span>or 4.2 x 30 x 80 Joules enery is required to heat 1 x 30 gm water by (100-20)*C( or required to be removed from water to cool it) </span>
I believe, that options 2. as well as 5. are the correct responses.
