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Mashcka [7]
3 years ago
12

Mention any two uses of oxygen gas.​

Chemistry
1 answer:
Elodia [21]3 years ago
3 0

Answer:

steel, plastics

<h3>Explanation:</h3>

Hope it helps!

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How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following
Oduvanchick [21]
4Li + O₂ = 2Li₂O

Li : Li₂O = 4 : 2 = 2 : 1

2 : 1
x : 4

x=4*2/1=8 mol

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6 0
3 years ago
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Consider the combustion of carbon monoxide (CO) in
Julli [10]

Answer:

3.60 mol CO₂

Explanation:

Balanced chemical reaction:

2CO + O₂ ⇒ 2CO₂

The molar ratio between CO₂ and CO is 1:1

2CO₂/2CO = CO₂/CO

Thus, the moles of CO₂ produced from 3.60 moles of CO is 3.60 moles:

(3.60 mol CO)(CO₂/CO) = 3.60 mol CO₂

6 0
3 years ago
A small amount of liquid bromine is added to a container which is then sealed.
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Answer:

This answer is....

Br2 (l)

8 0
3 years ago
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The process of converting nitrogen into nitrogen compounds by bacteria is called:
7nadin3 [17]
I believe this process is called fixation
7 0
3 years ago
A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume
MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas  = 7.70 litres

final pressure of the Krypton gas  = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the  Combined Gas Laws:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Rearranging the equation:

T1  = \frac{P1V1T2}{P2V2}

Putting the value in the equation:

T1 = \frac{0.960 X 6 X 323.15}{1.25 X 7.70}

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0
4 years ago
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