If iodine has a 13.3 hour half life, 3.12 mg of the original sample will still be present after 39.9 hours.
<h3>what is The meaning of half-life?</h3>
The reaction rate must decrease to half its initial value before the process has reached its half life. The split of that first order chemical reaction is a quantity related to the rate constant of the reaction.
Briefing:
Given, the iodine half-life is 13.3 hours. As a result, half-life t1/2 Equals ln 2/ K
k = 0.693 .... t1/2
≈ 0.693 /13.3 hours
= 5.21 *10-2
The rate law sets the flow timetime is set by the rate law, which varies for each emotion. When only one reactant's quantity influences the speed of chemical reaction, this is referred to as a first-order contact. Because of this, it is occasionally referred to as unimolecular process. The rate is as follows for this type of reaction: k= 1/t ln [A]0 / [A] is the rate constant for the first order reaction. 5.21 * 10-2 hours are in 39.9 hours.
By including all the numbers in the initial order reaction's rate constant equation, we obtain [A].
t = 3.12mg
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Answer:
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Answer:
Explanation:
Hello!
In this case, considering the given table, we are able to represent the symbolic rate law as shown below:
Thus, by using the following steps, we can find both m (BF3 order of reaction) and n (BF3 order of reaction):
- Experiment 1 and 2 for the calculation of n:
So we plug in to obtain:
So the order of reaction with respect to NH3 is 1.
- Experiment 3 and 4 for the calculation of m
So we plug in to obtain:
So the order of reaction with respect to BF3 is also 1.
Now, we can compute the rate constant by solving for it on any of the experiments there, say experiment 1:
Thus, the initial reaction rate for the 0.50M BF3 and 0.020M NH3 is:
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You are looking at a decomposition reaction because the original compound is being broken into its individual elements.<span />