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myrzilka [38]
3 years ago
10

The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?

Chemistry
1 answer:
charle [14.2K]3 years ago
6 0
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s =  154.9 mol/L
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Answer:

83.9g of sulfuric acid is the minimum mass you would need

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Based on the reaction:

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2 moles of solid aluminium react with 3 moles of sulfuric acid. Also, two moles of Al produce 3 moles of hydrogen gas.

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15.4g Al × (1mol / 26.98g) = 0.571 moles of Al.

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0.571 moles Al × (3 mol H₂SO₄ / 2 mol Al) = 0.8565 moles H₂SO₄

In grams:

0.8565 moles H₂SO₄ × (98g / 1mol) = <em>83.9g of sulfuric acid is the minimum mass you would need</em>

In the same way, moles of hydrogen produced are:

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