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3 years ago

The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?

1 answer:

6 0

Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L

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3 years ago

What does it mean that something is a conservative ion?

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3 years ago

Balance each skeleton reaction, use Appendix D to calculate E°cell, and state whether the reaction is spontaneous:(b) Hg₂²⁺(aq)

Olegator [25]

The given reaction is not spontaneous.

We must recognize changes in oxidation states that take place across elements in order to balance these equations. To accomplish this, keep in mind following guidelines:

A neutral element on its own has an oxidation number of zero.For a neutral molecule, the total number of oxidations must be zero.The net charge of an ion is equal to the sum of its oxidation numbers.In a compound: hydrogen prefers +1, oxygen prefers -2, fluorine prefers -1.In a compound with no oxygen present the other halogens will also prefer -1.

One of the mercury atoms is oxidized from +1 to +2 in the simple aqueous ion, for a loss of 1 electron.

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$0.5 Hg^{2+} _{2} (aq)$ → $Hg^{2+} (aq) + 1e^-$

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The other mercury is reduced from +1 to zero in mercury metal, for a gain of 1 electron.

Reduction half-reaction:

$0.5 Hg^{2+} _{2} (aq) + 1 e^-$ → $Hg(l)$

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This is a disproportionation redox reaction !

Net reaction:

$Hg^{2+} _{2} (aq)$ → $Hg^{2+} (aq) + Hg (l)$

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To learn more about the non spontaneous reaction please click on the link brainly.com/question/20358734

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2 years ago

If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it

Anna35 [415]

Answer:

121 K

Explanation:

Step 1: Given data

Initial volume (V₁): 79.5 mL

Initial temperature (T₁): -1.4°C

Final volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

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3 years ago

Si agrega un ácido a una base, ¿qué pasará?

egoroff_w [7]

Answer:

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4 years ago

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