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3 years ago

PLEASE HELPP!!

Chemistry

1 answer:

ankoles [38]3 years ago

4 0

You are exposed to nuclear radiation every day is true!

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What is the molality of a solution of 10 g NaOH in 500 g water? Molar mass NaOH = 40 g

umka2103 [35]

Explanation:

Moles of NaOH = 10g / (40g/mol) = 0.25mol.

0.25mol / 500g = 0.50mol / 1000g = 0.50mol/dm³.

The molarity is 0.50mol/dm³.

4 0

3 years ago

What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

1.58 mol CH₄

Step 2: Identify Conversions

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Convert

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

25.359 g CH₄ ≈ 25.4 g CH₄

4 0

3 years ago

Use chemical formulas to write the equation for the reaction between carbon and oxygen

yKpoI14uk [10]

C(5) + O2(g)

Hope this helped

3 0

3 years ago

MARK BRAINLIEST AND 14 POINTS

LekaFEV [45]

Answer:

She could prove that it is a combination of substances by looking for a change in color, or the formation of bubbles. She could also try to pull the combination apart by physical means alone.

Explanation:

4 0

3 years ago

Read 2 more answers

At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an

SOVA2 [1]

Answer: The equilibrium concentration of CO is 0.243 atm

Explanation:

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

$Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)$

Initial: 0.902

At eqllm: 3x (0.902-3x)

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

We are given:

$K_p=19.9$

Putting values in above equation, we get:

$19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810$

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0

3 years ago

Read 2 more answers