Answer: 25.37055324733817mol
Approximately 25.371mol
Explanation: Number of moles of a substance is the mass of that substance containing the same amount of fundamental units, for instance atom in 12.0g of 12°C
Therefore:
Number of moles= mass/ molecular mass
Where mass of fluorine given= 482g
Standard Molecular mass of fluorine= 18.9984032g/mol
Substituting value in equation
Mole= 482g/18.9984032g/mol = 25.37055324733817mol
Approximately : 25.371mol
Answer:
Chemical equation for photosynthesis
A water + carbon dioxide + sunlight → oxygen + glucose. B carbon + oxygen → carbon dioxide. C hydrogen + oxygen → water.
Explanation: This same photosynthesis cycle is usually expressed as: 6CO2 + 6H2O + 6O2 + C6H12O6. This implies that the solute, six carbon dioxide molecules plus 6 hydroxyl groups, are translated into something like a sugar molecule or six oxygen molecules, the goods, exploiting light energy absorbed the chlorophyll (implied by arrow).
(1) 36 days is 8 half-life periods,
so 24mg becomes 24mg times (1/2)^8 = 24 mg/256 = 0.094 mg
(2) 9.6/1.2 = 8, which means three half-life periods went by.
At the end of 4.5 days, there were 4.8 mg
At the end of 9.0 days, there were 2.4 mg
At the end of 13.5 days, there were 1.2 mg
(3) The activity is proportional to the amount of radioactive material remaining,
so after two half-life periods, the activity should be 1/4 of what it originally was.
So the initial activity was probably 12.0 Ci
Answer:
a that all you need and why you just and use a calculators and what they are for
Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
