Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
y1= 0, y2= 5/3
Step-by-step explanation:
Remove the parentheses and multiply
then cancel the equal terms
collect the lie terms
move the variables to one side
divide both sides by two
split into possible cases
then solve the equation to get
y= 0 and
y= 5/3
By definition you have that the tangent of an angle in a right triangle is given by the quotient between the sine of the angle and the cosine of the angle.
Since we know how much the sine and the cosine measure (we have the sides of the triangles as data), then the tangent is given by:
A. tan Y= y/z
answer
A. tan Y= y/z
Answer:
1) n= 20.5
2) t= -17/3
Step-by-step explanation:
1) -4n + 20 = -62
-4n = -82
n = 20.5
2) -3t = 17
t = -17/3
Answer:
Angle of A = 90 degree-62 degree = 28 degree.
Step-by-step explanation:
tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319
cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3
or another way.
sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3
So Angle of A = 28 degree.
a = 5. 3
c = 11.3.
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